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fenix001 [56]
3 years ago
8

4. Tim's family just got back from a vacation. They had been traveling for 2 days, driving 11

Mathematics
1 answer:
dangina [55]3 years ago
4 0
22 hours all together
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An important part of customer service responsibilities of a cable company relates to the speed with which trouble in service can
fenix001 [56]
The answer to your question is
D.  .2373


Hope this helps

5 0
3 years ago
Read 2 more answers
If sec 48 = 1.4945, find csc 42
Grace [21]
Because cos(x) = 1/sec(x), therefore
cos(48) = 1/1.4945 = 0.6691

The angle 48° is in quadrant 1, therefore cos, sin, tan, sec, csc and cot functions are all positive.

Note that sin(90° - x) = cos(x).
Therefore
sin(90 - 48) = cos(48)
sin(42°) = cos(48°) = 0.6691

Because csc(x) = 1/sin(x), therefore
csc(42°) = 1/sin(42°) = 1/0.6691 = 1.4945

Answer:  1.4945
3 0
3 years ago
I’m confused about these questions. Compositions and inverses ⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️
Alekssandra [29.7K]

9514 1404 393

Answer:

  1. (f+g)(x) = 2x^2 +4x +2

  2. (f -g)(x) = -2x^2 +4x -4

  5. (f+g)(x) = x^2 +2x -1

  6. (g -f)(x) = x^2 -2x -1

Step-by-step explanation:

None of these are compositions. They are only sums or differences.

  (f±g)(x) = f(x) ± g(x)

__

1. (f+g)(x) = f(x) +g(x) = (4x -1) +(2x^2 +3)

  (f+g)(x) = 2x^2 +4x +2

__

2. (f -g)(x) = f(x) -g(x) = (4x -1) -(2x^2 +3)

  (f -g)(x) = -2x^2 +4x -4

__

5. (f +g)(x) = f(x) +g(x) = (2x) +(x^2 -1)

  (f+g)(x) = x^2 +2x -1

__

6. (g -f)(x) = g(x) -f(x) = (x^2 -1) -(2x)

  (g -f)(x) = x^2 -2x -1

7 0
3 years ago
PLEASE HELP I REALLY WANNA PASS , Im trying to post this image ILL GIVE A MEDAL
bogdanovich [222]
Older then 35, hemo. less then 9.....76/162 = 0.47
younger then 25, hemo. above 11....69/139 = 0.50
25-35 age group, hemo. less then 9...32/128 = 0.25
older then 35, hemo. between 9 and 11...46/162 = 0.28


4 0
3 years ago
Read 2 more answers
What is the surface area of this cube
Sedaia [141]

Answer:

surface area of cube is 6a² where a is side of the cube

6 0
3 years ago
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