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First compute the component form of vector u by subtracting its initial values from terminal values. 18-1=17, 6-(-12)=18. So u=(17, 18). Since v points in the opposite direction, and has a magnitude three times that of u, we multuply the u by -3 and get v=(-3*17, -3*18)=(-51, -54).
First we set up an equation with the givens (slope and y intercept):
y = 2x -4
next plug in 6 for x.
y = (2x6) - 4
y = 12 - 4
And this will give us the value of y: 8.
It's the absolute value which is 8
Answer:
(a) a ≈ 22.7 meters, (b) c ≈ 10.6 meters, (c) ∠A = 65°
Step-by-step explanation:
assuming side a/c is side BC/AB since it's opposite of angle A/C
(a) SOH CAH<em>(cos = </em><em>adjacent side/hypotenuse</em><em>)</em> TOA
=> cos (25°) = BC/AC or a/b
=> cos (25°) = a/25
=> a = cos (25°) × 25
=> a ≈ 22.7
(b) SOH<em>(sin = </em><em>opposite side/hypotenuse</em><em>)</em> CAH TOA
=> sin (25°) = AB/AC or c/b
=> sin (25°) = c/25
=> c = sin (25°) × 25
=> c ≈ 10.6
(c) 180° - 25° - 90°(the right angle) = 65°
