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luda_lava [24]
3 years ago
11

Ethan decided to type up some documents while waiting for the meeting to start. he can type 2 pages every 1/8 hours. if the meet

ing started 3/4 hour later than the scheduled time, how many pages can he type before the meeting starts
Mathematics
1 answer:
anzhelika [568]3 years ago
7 0

Answer:

Ethan can type 6 pages before meeting starts.

Step-by-step explanation:

Given that,

Ethan can type 2 pages in 1/8 hours

and his meeting is 3/4 hours late.

To find,

number of pages Ethan can type in 3/4 hours

<h3>1) </h3><h3>convert hours to minutes</h3>

1 hour      = 60 minutes

1/8 hours = 1/8 * 60

               = 7.5 minutes

3/4 hours = 3/4 * 60

                = 45 minutes

<h3>2) </h3><h3>calculate pages typed</h3>

7.5 minutes     = 1 page typed

    1 minute      = 1/7.5 pages typed

    45 minutes = (1/7.5) * 45

                        = 6 pages typed

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8 0
3 years ago
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Based on the information below, choose the correct answers. Note: The monthly loan payment was calculated at 119 payments of $33
Margaret [11]

Answer:

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  • 36.94%

Step-by-step explanation:

a) The amount of concern is ...

  (total interest)/(number of payments) = interest/payment

  $14,644.95/120 ≈ $122.04 . . . . amount of interest per payment

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b) The ratio of concern is ...

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  ≈ 36.94% . . . . percent of total payments that is interest

6 0
3 years ago
Two boxes of tea weight 3 oz. The Tea Time Tasty Tea Company packs 112 boxes in a case of tea. How many pounds does each case of
Marysya12 [62]
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6 0
3 years ago
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Julie and Eric row their boat (at a constant speed) downstream for 40 miles in 4 hours, helped by the current. Rowing at the sam
Liula [17]

Answer: 3 miles per hour

<u>Step-by-step explanation:</u>

Use the formula "distance (d) = rate (r) x time (t)" to create a system of equations.

Let "r" represent the rate they are rowing

Let "c" represent the current

                            time          rate      distance        <u>EQUATION</u>

Downstream:     4 hours     r + c       40 miles         4(r + c) = 40

Upstream:         10 hours    r - c        40 miles         10(r - c) = 40


Distribute, then eliminate r to solve for c:

Down: 4r + 4c = 40  →   5(4r + 4c = 40)  →   20r + 20c = 200

  Up: 10r - 10c = 40  → -2(10r - 10c = 40) → <u>-20r + 20c</u> =<u>  -80</u>

                                                                                40c = 120

                                                                              <u> ÷40  </u>  <u>÷40 </u>

                                                                                    c =   3

4 0
3 years ago
A student group claims that first-year students at a university must study 2.5 hours (150 minutes) per night during the school w
AlekseyPX

Answer:

We have strong evidence that on average, students study less than 150 minutes per night during the school week

Step-by-step explanation:

Normal distribution:

mean     μ₀ = 150

Sample:

Sample size    n = 272

Sample mean   x = 141

Sample standard deviation  s  = 66

The standard error of the sample mean  SE = σ /√n

SE = 66/√272

SE = 66 / 16,49

SE = 4

Test Hypothesis:

Null hypothesis                            H₀             x  =   μ₀

Alternative hypothesis                Hₐ            x <    μ₀

z(s)  test statistics is:

z(s)  =  ( x  -  μ₀ ) / s/√n

z(s) = - 9 /4

z(s) =  -  2,25

p-value  for that z(s)      p-value  = 0,0122

Then for α =  0,05 p-value < 0,05

We are in the rejection region we need to reject H₀

7 0
3 years ago
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