The parabola is opens upward.
a = (8 – 5)
= 3
Using the standard form:
(x – h)^2 = 4a(y – k)
(x -5)^2 = 12( y – 4)
In general form
x^2 -10x +25 =12y – 48
x^2 -10x -12y + 73 =0
In order to find height from where ball is dropped, you have to find height or h(t) when time or t is zero.So plug in t=0 into your quadratic equation:h(0) = -16.1(0^2) + 150h(0) = 0 +150h(0) = 150 ft is the height from where ball is dropped. When ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.0 = -16.1t^2 + 15016.1 t^2 = 150t^2 = 150/16.1t = sqrt(150/16.1)t = ± 3.05Since time cannot be negative, your answer is positive solution i.e. t = 3.05
Average speed = 24 3/4 / 1 1/2 = 99/4 / 3/2 = 99/4 x 2/3 = 16 1/2 miles per hour.
Answer:
According to the passage, we have the next equation:

where "K" is a proportional constant
Leaving at the end with the next equation:

Integrating the equation, we have:

where "C" is a constant
Then, we have the 2 conditions for the problem:
1) t=0 → r=10
Replacing in the equation, we have C = 10
2) t=5 → r=8
Replacing in the equation, we have K = -0.4
Finally, the time which the snowball will be completely melted will be when r = 0. So replacing in the equation

t = 25 minutes