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3 years ago

The radius of a circle is 1 centimeter. What is the area of a sector bounded by a 90 arc

Mathematics

2 answers:

tensa zangetsu [6.8K]3 years ago

4 0

Given

radius (r) = 1 cm

thita = 90°

We have the formula to calculate area of sector which is

Area = (thita/ 360°) πr²

 = 90°/360° * 3.14 * 1²

 = 0.25 * 3.14 * 1

 = 0.785 cm²

MrRissso [65]3 years ago

3 0

Answer:

1/4nr is the right answer i took the test

Step-by-step explanation:

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vodomira [7]

Answer:

No, and this isn't the place to put an ad

Step-by-step explanation:

4 0

2 years ago

-4r-8(r-6)=7(5r-1)+8

KATRIN_1 [288]

Answer:

r = 1

Step-by-step explanation:

In this question, we have to solve for the vallue of "r". We will use the distributive property shown below to ease our process.

Distributive Property:

a(b+c) = ab + ac

Now, lets solve this:

$-4r-8(r-6)=7(5r-1)+8\\-4r-8r+48=35r-7+8\\-12r+48=35r+1\\48-1=35r+12r\\47=47r\\r=\frac{47}{47}\\r=1$

As we have seen the value of r is "1"

6 0

3 years ago

117.369 is 24 3/10% of what number?

Tanya [424]

Let's look at the equation:
0.243x=117.369
Divide each side by 0.243.
X=483
So, the number is 483.

4 0

3 years ago

Evaluate f^3+11g-4h when f= 3, g=2 and h=7

vladimir2022 [97]

Step-by-step explanation:

=f³+11×g-4×h

=3³+11×2-4×7

=27+22-28

=21

is yr answer.

3 0

3 years ago

Plz help me with this

Setler79 [48]

Answer: x = 8

(the correct answer was not provided as an option)

Step-by-step explanation:

$log_2(x-6)+log_2(x-4)=log_2(x)\\\\log_2[(x-6)(x-4)]=log_2(x)\\\\(x-6)(x-4)=x\\\\x^2-10x+24=x\\\\x^2-11x+24=0\\\\(x-3)(x-8)=0\\\\x=3\qquad x=8\\\\\\\text{The term after the log symbol (inside the parenthesis) must be greater than 0!}\\\\Check:\\3-6>0\ \text{FALSE --- so 3 is not a valid solution}\\\\8-6>0\ \text{TRUE}\\8-4>0\ \text{TRUE}\\8>0\ \text{TRUE --- 8 is a valid solution because it is true for all}$

8 0

3 years ago