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3 years ago

13

The function f(x) has been transformed to give g(x). Which of the following functions represent g(x)

2 answers:

enot [183]3 years ago

3 0

Answer:

Option A is correct.

Step-by-step explanation:

See the two graphs given in the diagram attached.

The first graph shows the function f(x) = x²

Hence, it passes through the points (1,1), (-1,1), (2,4) and (-2,4) points.

Now, from the plotted second graph we see the points (2,2), and (-2,2) are on the curve.

Hence, the y-value corresponding to the same x-value reduces by a factor $\frac{1}{2}$ in the second graph i.e. the graph of y = g(x) compared to the first graph.

So, we can conclude that the transformed graph has the equation $g(x) = \frac{1}{2} x^{2}$ .

Hence, option A is correct. (Answer)

lana66690 [7]3 years ago

3 0

Answer: A

Step-by-step explanation:

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Consider the functions given below. SEE F

Wewaii [24]

Answer:

1. $P(x)$ ÷ $Q(x)$ ---> $\frac{-3x + 2}{3(3x - 1)}$

2. $P(x) + Q(x)$ ---> $\frac{2(6x - 1)}{(3x - 1)(-3x + 2)}$

3. $P(x) - Q(x)$ ---> $\frac{-2(12x - 5)}{(3x - 1)(-3x + 2)}$

4. $P(x)*Q(x)$ --> $\frac{12}{(3x - 1)(-3x + 2)}$

Step-by-step explanation:

Given that:

1. $P(x) = \frac{2}{3x - 1}$

$Q(x) = \frac{6}{-3x + 2}$

Thus,

$P(x)$ ÷ $Q(x)$ = $\frac{2}{3x - 1}$ ÷ $\frac{6}{-3x + 2}$

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

$\frac{2}{3x - 1}*\frac{-3x + 2}{6}$

$\frac{2(-3x + 2)}{6(3x - 1)}$

$= \frac{-3x + 2}{3(3x - 1)}$

2. $P(x) + Q(x)$ = $\frac{2}{3x - 1} + \frac{6}{-3x + 2}$

Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

$\frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 4 + 18x - 6}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 18x + 4 - 6}{(3x - 1)(-3x + 2)}$

$\frac{12x - 2}{(3x - 1)(-3x + 2)}$

$= \frac{2(6x - 1}{(3x - 1)(-3x + 2)}$

3. $P(x) - Q(x)$ = $\frac{2}{3x - 1} - \frac{6}{-3x + 2}$

$\frac{2(-3x + 2) - 6(3x - 1)}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 4 - 18x + 6}{(3x - 1)(-3x + 2)}$

$\frac{-6x - 18x + 4 + 6}{(3x - 1)(-3x + 2)}$

$\frac{-24x + 10}{(3x - 1)(-3x + 2)}$

$= \frac{-2(12x - 5}{(3x - 1)(-3x + 2)}$

4. $P(x)*Q(x) = \frac{2}{3x - 1}* \frac{6}{-3x + 2}$

$P(x)*Q(x) = \frac{2*6}{(3x - 1)(-3x + 2)}$

$P(x)*Q(x) = \frac{12}{(3x - 1)(-3x + 2)}$

4 0

4 years ago

2x2-3 evaluate each expression. Show your work

nirvana33 [79]

Answer:

1

Step-by-step explanation:

2x2 = 4

4-3=1

5 0

4 years ago

(6x + 7) - (9x + 9) simpilest form pls

My name is Ann [436]

Answer:

-3x+16

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Gale wants to compare the cost of the events.

Lera25 [3.4K]

#a

The table represents all possibilities.

Yes its possible .
The table may represent Aquarium fee more or least etc.

#b

The carnival always costs the least.

No its possible but not always .
Aquarium fee is 14.50 on the other hand carnival fee starts at 15.55.

#c

The aquarium always costs the move.

Impossiible

8 0

2 years ago

Find the diameter of a circle with an area of<br>95.03 square feet.<br>

ra1l [238]

For this case we have that the area of a circle is given by:

$A = \pi * r ^ 2$

Where:

r: It is the radius of the circle

By clearing the radio we have:

$r = \pm \sqrt {\frac {A} {\pi}}$

We take the positive value:

$r = \sqrt {\frac {A} {\pi}}\\r = \sqrt {\frac {95.03} {\pi}}\\r = 5.50 \ ft$

The diameter is twice the radius:

$d = 11$

Answer:

$11 \ ft$

7 0

3 years ago

Read 2 more answers