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2 years ago

14

If you bought a stock last year for a price of $68, and it has gone down 6.5% since then how much is the stock worth now, to the

nearest cent?

1 answer:

trapecia [35]2 years ago

7 0

Answer:

Step-by-step explanation:

10.4615384615

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(Question 2 : Select the best answer for the question.)

iris [78.8K]

Answer:

B is the answer i think

Step-by-step explanation:

because its lenear and positive...

5 0

3 years ago

Can someone find the slope

Alex787 [66]

Hello!

The slope is in rise over run form

From point to point to goes up 4 and over 10

that is 4/10

This can be simplified to 2/5

The answer is 2/5

Hope this helps!

4 0

2 years ago

Read 2 more answers

V(t)=26,000(0.90^t) find the initial value and the value after 11 years

Damm [24]

Well you're given the equation and the time.

substitute:

V(t) = 26,000(0.90^t)
V(11) = 26,000(0.90^(11))
V(11) = 8,159.075498
V(11) ≈ 8,159

5 0

3 years ago

Sally can paint a room in 4 hours while it takes steve 9 hours to paint the same room. how long would it take them to paint the

Eva8 [605]

Sally ⇒
4 hours = 1 room
1 hour = 1/4 of the room

Steve ⇒
9 hours = 1 room
1 hour = 1/9 of the room

Sally + Steve ⇒
1 hour = 1/4 + 1/9 = 9/36 + 4/36 = 13/36

Number of hours needed ⇒
1 ÷ 13/36 = 1 x 36/13 = 36/13 = 2 10/13 hours

Answer: They need 2 10/13 hours.

7 0

2 years ago

Is the graph of y = sin(x^4) increasing or decreasing when x = 10? Is it concave up or concave down?

Tanzania [10]

$y=\sin(x^4)$
$\implies y'=4x^3\cos(x^4)$
$\implies y'=12x^2\cos(x^4)-16x^6\sin(x^4)$

At $x=10$ , you have

$y'(10)=4000\cos(10^4)$

The trick to finding out the sign of this is to figure out between which multiples of $\dfrac\pi2$ the value of $10^4$ lies.

We know that $\cos x>0$ whenever $-\dfrac\pi2+2n\pi$ , and that $\cos x$ whenever $\dfrac\pi2+2n\pi$ , where $n\in\mathbb Z$ .

We have

$10^4=\dfrac{k\pi}2\implies k=\dfrac{2\times10^4}\pi\approx6366.2$

which is to say that $\dfrac{6366\pi}2$ , an interval that is equivalent modulo $2\pi$ to the interval $\left(\pi,\dfrac{3\pi}2\right)$ .

So what we know is that $10^4$ corresponds to the measure of an angle that lies in the third quadrant, where both cosine and sine are negative.

This means $y'(10)$ , so $y$ is decreasing when $x=10$ .

Now, the second derivative has the value

$y'=12\times10^2\cos(10^4)-16\times10^6\sin(10^4)$

Both $\cos(10^4)$ and $\sin(10^4)$ are negative, so we're essentially computing the sum of a negative number and a positive number. Given that $\sin x>\cos x$ for $\pi$ , and $\cos x>\sin x$ for $\dfrac{5\pi}4$ , we can use a similar argument to establish in which half of the third quadrant the angle $10^4$ lies. You'll find that the sine term is much larger, so that the second derivative is positive, which means $y$ is concave up when $x=10$ .

5 0

3 years ago