Question

What is the length of the line segment with endpoints (−3,8) and (7, 8) ? Enter your answer in the box

Answer 1

Length = √(y2-y1)² + (x2-x1)²
l = √(8-8)² + (7+3)²
l = √10²
l = 10

In short, Your Answer would be 10 units

Hope this helps!

Answer 2

Answer:

10 units

Step-by-step explanation:

$(x_1,y_1)=(-3,8)$

$(x_2,y_2)= (7, 8)$

We are supposed to find the length of the line segment with endpoints (−3,8) and (7, 8)

We will use distance formula : $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the values :

$d=\sqrt{(7+3)^2+(8-8)^2}$

$d=\sqrt{100}$

$d=10$

Hence the length of the line segment with endpoints (−3,8) and (7, 8) is 10 units