f(h(x))= 2x -21
Step-by-step explanation:
f(x)= x^3 - 6
h(x)=\sqrt[3]{2x-15}
WE need to find f(h(x)), use composition of functions
Plug in h(x)
f(h(x))=f(\sqrt[3]{2x-15})
Now we plug in f(x) in f(x)
f(h(x))=f(\sqrt[3]{2x-15})=(\sqrt[3]{2x-15})^3 - 6
cube and cube root will get cancelled
f(h(x))= 2x-15 -6= 2 x-21
wait i think i did the wrong one brb
$18.11 because 20.75/x=100/15
<span>(120.75/x)*x=(100/15)*x - </span>we multiply both sides of the equation by x
<span>120.75=6.6666666666667*x - </span>we divide both sides of the equation by (6.6666666666667) to get x
<span>120.75/6.6666666666667=x </span>
<span>18.1125=x </span>
<span>x=18.1125</span>
4(x - 2) + 6 = 2(5x - 6) <em>use distributive property</em>
(4)(x) + (4)(-2) + 6 = (2)(5x) + (2)(-6)
4x - 8 + 6 = 10x - 12
4x - 2 = 10x - 12 <em>add 2 to both sides</em>
4x = 10x - 10 <em>subtract 10 from both sides</em>
-6x = -10 <em>divide both sides by (-6)</em>
x = 10/6
<h3>x = 5/3</h3>