Triangle ABC has been translated to create triangle A'B'C'. Angles C and C' are both 32 degrees, angles B and B' are both 72 deg
rees, and sides BC and B'C' are both 5 units long. Which postulate or theorem below would prove the two triangles are congruent?
2 answers:
Δ ABC and Δ A'B'C' are congruent.
Proof: BC = B'C' = 5 units (given)
Angle B = Angle B' = 72° (given)
Angle C = Angle C' = 32° (given)
The 2 tringles are ten equal ASA
Answer:
ΔABC ≅ ΔA'B'C' are congruent by ASA postulate
Step-by-step explanation:
Let's draw ΔABC and ΔA'B'C'
<u>Statement Reason</u>
i) ∠C = ∠C' = 32° Given
ii) ∠B = ∠B' = 72° Given
iii) BC = B'C' = 5 Given
IV) ΔABC ≅ ΔA'B'C' If two angles and the included
side of one triangle equal to the
corresponding angles and
included side of another triangle
then the two triangles are
congruent. By ASA postulate.
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