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sergey [27]
3 years ago
12

Triangle ABC has been translated to create triangle A'B'C'. Angles C and C' are both 32 degrees, angles B and B' are both 72 deg

rees, and sides BC and B'C' are both 5 units long. Which postulate or theorem below would prove the two triangles are congruent?

Mathematics
2 answers:
Murrr4er [49]3 years ago
8 0
Δ ABC and Δ A'B'C' are congruent.

Proof: BC = B'C' = 5 units (given)

Angle B = Angle B' = 72° (given)
Angle C = Angle C' = 32° (given)

The 2 tringles are ten equal ASA

Karo-lina-s [1.5K]3 years ago
6 0

Answer:

ΔABC ≅ ΔA'B'C' are congruent by ASA postulate

Step-by-step explanation:

Let's draw ΔABC and ΔA'B'C'

<u>Statement                                                 Reason</u>

i) ∠C = ∠C' = 32°                                            Given

ii) ∠B = ∠B' = 72°                                            Given

iii) BC = B'C' = 5                                              Given

IV) ΔABC ≅ ΔA'B'C'                                        If two angles and the included

                                                                        side of one triangle equal to the

                                                                        corresponding angles and

                                                                        included side of another triangle

                                                                        then the two triangles are

                                                                        congruent. By ASA postulate.

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