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Liula [17]
3 years ago
15

Find the number which divides 200 and 136 leaving 8 as remainder.

Mathematics
2 answers:
marta [7]3 years ago
8 0
Two ways to find.
1. Find n Natural numbers that 136/n gives reminder 8. and check with 200. Bad Way.
2. Logic way. ... Find Greatest common divisor of 200+8 and 136+8. GCD(208;144)=(64;144)=(64;80)=(64;16). 64 is divisible by 16 so 16 is the answer . check 200/16 reminder 8 so 136/8
TEA [102]3 years ago
8 0

Answer:16,32,64

Step-by-step explanation:

Given no divides 200 and 136 leaving remainder 8

Let no. be P

therefore

200=kP+8

where k is any constant

136=aP+8

where a is another constant

subtracting

64=P(k-a)

i.e.P is multiple of 64

either 64,32,16

but not 8,4,2 as they completely divide both numbers

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Answer:

x = 6

<u><em>Sorry if this answer is not correct, if it is or is not, please tell me in the comments!</em></u>

Step-by-step explanation:

All of the angles add up to 180 degrees (since it is a triangle), so

(11x - 3) + (7x + 5) + (13x - 8) = 180

Then, combine the like terms.

31x - 6 = 180

Now, out goal is to separate the x from everything. To do that, we need to add 6 to 180.

31x = 186

Then divide by 31.

x = 6

(Feel free to replace x with 6 back in the previous equation to double check it!)

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2 years ago
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Step-by-step explanation:

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What is the reciprocal of 2⅜​
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Step-by-step explanation:

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Duncan shares 20 percent of all of his sales commissions with his personal assistant. If Duncan earns x dollars in commissions a
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3 0
2 years ago
Se sabe q la suma de tres numeros es de 850. El primer es un tercio del segundo y el tercer número es el doble del segundo.¿Cual
murzikaleks [220]

Answer:

Primer número = x = 85

Segundo número = y = 255

Tercer número = z = 510

Step-by-step explanation:

Se sabe que la suma de tres números es 850. El primero es un tercio del segundo y el tercer número es el doble del segundo.

Representamos:

Primer número = x

Segundo número = y

Tercer número = z

Se sabe que la suma de tres números es 850.

x + y + z = 850 ...... Ecuación 1

El primero es un tercio del segundo

x = 1/3 años

El tercer número es el doble del segundo.

z = 2 años

Sustituimos 1 / 3y por x y 2y por z en la Ecuación 1

1 / 3y + y + 2y = 850

y / 3 + 3y = 850

Multiplica ambos lados por 3

y + 9y = 850 × 3

10 años = 2550

y = 2550/10

y = 255

Resolviendo para x

x = 1/3 años

x = 1/3 × 255

x = 85

z = 2 años

z = 2 × 255

z = 510

Por eso,

Primer número = x = 85

Segundo número = y = 255

Tercer número = z = 510

5 0
3 years ago
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