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Novay_Z [31]
2 years ago
9

John and Jessica are selling fruit for a school fundraiser. Customers can buy small boxes of tangerines and large boxes of tange

rines. John sold 7 small boxes of tangerines and 13 large boxes of tangerines for a total $165. Jessica sold 1 small box of tangerines and 13 large boxes of tangerines for a total $135. What is the cost of each of one small box of tangerines and one large box of tangerines?
Mathematics
2 answers:
sattari [20]2 years ago
6 0

Answer:

small box: $5

large box: $10

Step-by-step explanation:

VARVARA [1.3K]2 years ago
3 0

Answer: Small box: $13; Large box: $16

Step-by-step explanation:

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Please help?
Mazyrski [523]

Answer:

23\sqrt{3}\ un^2

Step-by-step explanation:

Connect points I and K, K and M, M and I.

1. Find the area of triangles IJK, KLM and MNI:

A_{\triangle IJK}=\dfrac{1}{2}\cdot IJ\cdot JK\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 2\cdot 3\cdot \dfrac{\sqrt{3}}{2}=\dfrac{3\sqrt{3}}{2}\ un^2\\ \\ \\A_{\triangle KLM}=\dfrac{1}{2}\cdot KL\cdot LM\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 8\cdot 2\cdot \dfrac{\sqrt{3}}{2}=4\sqrt{3}\ un^2\\ \\ \\A_{\triangle MNI}=\dfrac{1}{2}\cdot MN\cdot NI\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 3\cdot 8\cdot \dfrac{\sqrt{3}}{2}=6\sqrt{3}\ un^2\\ \\ \\

2. Note that

A_{\triangle IJK}=A_{\triangle IAK}=\dfrac{3\sqrt{3}}{2}\ un^2 \\ \\ \\A_{\triangle KLM}=A_{\triangle KAM}=4\sqrt{3}\ un^2 \\ \\ \\A_{\triangle MNI}=A_{\triangle MAI}=6\sqrt{3}\ un^2

3. The area of hexagon IJKLMN is the sum of the area of all triangles:

A_{IJKLMN}=2\cdot \left(\dfrac{3\sqrt{3}}{2}+4\sqrt{3}+6\sqrt{3}\right)=23\sqrt{3}\ un^2

Another way to solve is to find the area of triangle KIM be Heorn's fomula, where all sides KI, KM and IM can be calculated using cosine theorem.

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3 years ago
Jake Kim and lee share some money in the ratio 1:3:6. Kin gets £9 more than jake. How much does lee get?
Serga [27]
3=12
1=3
6=24 lee has the 6 ratio therefore he gets 24. I worked this out on the basis that has 9 more than jake not nine all together.
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