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Igoryamba
3 years ago
12

Special precision bolts are made by another machine. These are for jobs that require more exact measurements. The bolts must be

within 0.01 mm of 8 mm. This is represented by |x – 8| < 0.01. 

Write this inequality as a compound inequality without absolute value bars.

Solve the inequality.
Graph the solutions on a number line.
What do the solutions of the inequality mean for the bolt?
Mathematics
1 answer:
klio [65]3 years ago
3 0

The solutions of the inequality is 7.99<x<8.01. I think this solutions means the radius of hole in the bolt or something along that, but I'm not sure.

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3 years ago
The scores on the entrance exam at a well-known, exclusive law school are normally distributed with a mean score of 200 and a st
ruslelena [56]

Answer:

the lowest passing score would be x = 298

Step-by-step explanation:

School wishes that only 2.5 percent of students taking test pass

We are given

mean= 200,

standard deviation = 50

We need to find x

The area under the curve can be found by:

2.5 % = 0.025

So, 1- 0.025 = 0.975

We need to find the value of z for which the answer is 0.975

Looking at the z-score table, the value of z is: 1.96

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1.96 = x - 200/50

=> 1.96 * 50 = x-200

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=> x = 200+98

x = 298

So, the lowest passing score would be x = 298

8 0
3 years ago
The graph below shows the solution to which system of inequalities
Oksi-84 [34.3K]
The answer is
the option A
<span>The graph shows the solution of the system of inequalities
y> -3
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5 0
3 years ago
Read 2 more answers
I don't know how to do this or what i'm doing plz help
mote1985 [20]

recalling that d = rt, distance = rate * time.


we know Hector is going at 12 mph, and he has already covered 18 miles, how long has he been biking already?


\bf \begin{array}{ccll} miles&hours\\ \cline{1-2} 12&1\\ 18&x \end{array}\implies \cfrac{12}{18}=\cfrac{1}{x}\implies 12x=18\implies x=\cfrac{18}{12}\implies x=\cfrac{3}{2}


so Hector has been biking for those 18 miles for 3/2 of an hour, namely and hour and a half already.

then Wanda kicks in, rolling like a lightning at 16mph.

let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.

the distance both have travelled is the same "d" miles, reason why they "meet", same distance.


\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}


\bf \stackrel{\textit{substituting \underline{d} in the 2nd equation}}{\boxed{(12)\left( t+\frac{3}{2} \right)}=16t}\implies 12t+18=16t \\\\\\ 18=4t\implies \cfrac{18}{4}=t\implies \cfrac{9}{2}=t\implies \stackrel{\textit{four and a half hours}}{4\frac{1}{2}=t}

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Find the answer in the attachment

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