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Gwar [14]
3 years ago
10

Basketballs cost $17 each. Adam purchased 8 basketballs for $136. Which equation uses the distributive property to show that Ada

m spent $136 on 8 basketballs? A) 8 x 17 = 136 B) 8 × (10 + 7) = 136 C) 17 + 17 + 17 + 17 + 17 + 17 + 17 + 17 = 136 D) 136 ÷ 17 = 8
Mathematics
1 answer:
arlik [135]3 years ago
3 0

Answer:

c

Step-by-step explanation: because if you add  all of the 17's you will get 136 in total

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Tell whether I and y are proportional<br><br> PLS HELP
pentagon [3]

Answer:

This is not proportional. In order for it to be proportional the number from dividing y/x must be the same all the way through. Example:18/2=9 20/4=5

The answers are not the same, therefore x and y are not proportional. Hope this helped.

Step-by-step explanation:

8 0
2 years ago
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Please help asap! I need this done tomorrow ​
d1i1m1o1n [39]

Answer:

2x + 3y = 4

Step-by-step explanation:

The standard form:

Ax + By = C

So from the given form, arrange it to the standard form.

First, simplify the form by distribution.

y + 6 = -2/3(x - 11)

y + 6 = -2/3x + 22/3

Next, you make the fractions into whole by multiplying both sides by 3(this would eliminate all fractions).

(3)y + 3(6) = 3(-2/3x) + 3(22/3)

3y + 18 = -2x + 22

Now, arrange the "Ax" and the "C's".

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Cheers!

6 0
3 years ago
Is this table linear, exponential or quadratic?
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Answer:

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1 year ago
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A collection of coins consists of nickels, dimes, and quarters. There are three fewer quarters than nickels and six more dimes t
weeeeeb [17]

Answer:

You have 15 dimes. You have 9 quarters. You have 12 nickels

Step-by-step explanation:

lets set some variables:

let "n" = the number of nickels

let "d" = the number of dimes

let "q" = the number of quarters

So, the total amount of money you have should be: $4.35 = 0.25q + 0.10d + 0.05n

Now let's look at the relationships between the coins:

"There are three fewer quarters than nickels": n - 3 = q

"six more dimes than quarters": q + 6 = d

So now you have three equations with three variables, all you need to do is solve.

\left \{ {{4.35 = 0.25q + 0.10d + 0.05n} \atop {n - 3 = q}} \atop {q + 6 = d}}\right.

first, you can substitute "n-3" for "q" (according to the 2nd equation) in the 1st and 3rd equation, you get:

\left \{ {{4.35=0.25(n-3)+0.10d+0.05n} \atop {(n-3)+6=d}} \right.

You now only have two equations and two variables.

Simplify:

\left \{ {{4.35=0.25n-0.75+0.10d+0.05n} \atop {n+3=d}} \right.

\left \{ {{4.35=0.30n-0.75+0.10d} \atop {n+3=d}} \right.

Now substitute "n+3" for "d" (according to the 2nd equation) in the 1st equation:

4.35=0.30n-0.75+0.10(n+3)

simplify:

4.35=0.30n-0.75+0.10n+0.30

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Answer:

Future Value= $112.72

Step-by-step explanation:

Giving the following information:

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FV= PV*(1 + i)^n

FV= 100*(1.005^24)

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5 0
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