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Dimas [21]
3 years ago
6

8y+14=3y+49 solve as equations

Mathematics
2 answers:
mamaluj [8]3 years ago
8 0

Answer:

8y+14=3y+49

8y-3y+14=3y-3y+49

5y+14=49

5y+14-14=49-14

5y=35

Divide by 5

5y/5=35/5

y=7

Check answer by using substitution method

8(7)+14=3(7)+49

70=70

Answer is y=7

Simora [160]3 years ago
5 0

Answer:

Step-by-step explanation:

8y+14=3y+49

-3y .      -3y

5y+14=49

     -14   -14

5y=35       divide both sides by 5

y=7

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A= [1, 3; 2, 1], B=[3, 6; -1, 1]. Find AB &amp; BA if possible
steposvetlana [31]

Answer:

AB\Rightarrow \quad \begin{bmatrix}0 & 9\\ 5 & 13\end{bmatrix}\\BA\Rightarrow \quad \begin{bmatrix}15 & 15\\ 1 & -2\end{bmatrix}

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Since A is a 2×2 matrix and B is also a 2×2 matrix

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So AB is:

AB\Rightarrow\begin{bmatrix}1 & 3\\ 2 & 1\end{bmatrix}\begin{bmatrix}3 & 6\\ -1 & 1\end{bmatrix}\\AB\Rightarrow\quad \begin{bmatrix}3\times 1+3\times (-1) & 6\times 1+3\times 1\\3\times 2+1\times (-1) & 6\times 2+1\times 1\end{bmatrix}\\AB\Rightarrow \quad \begin{bmatrix}0 & 9\\ 5 & 13\end{bmatrix}

BA is:

BA\Rightarrow\begin{bmatrix}3 & 6\\ -1 & 1\end{bmatrix}\begin{bmatrix}1 & 3\\ 2 & 1\end{bmatrix}\\BA\Rightarrow\quad \begin{bmatrix}3\times 1+6\times 2 & 3\times 3+6\times 1\\(-1)\times 1+1\times 2 & (-1)\times 3+1\times 1\end{bmatrix}\\BA\Rightarrow \quad \begin{bmatrix}15 & 15\\ 1 & -2\end{bmatrix}

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3 years ago
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2 years ago
Read 2 more answers
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