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Dimas [21]
3 years ago
6

8y+14=3y+49 solve as equations

Mathematics
2 answers:
mamaluj [8]3 years ago
8 0

Answer:

8y+14=3y+49

8y-3y+14=3y-3y+49

5y+14=49

5y+14-14=49-14

5y=35

Divide by 5

5y/5=35/5

y=7

Check answer by using substitution method

8(7)+14=3(7)+49

70=70

Answer is y=7

Simora [160]3 years ago
5 0

Answer:

Step-by-step explanation:

8y+14=3y+49

-3y .      -3y

5y+14=49

     -14   -14

5y=35       divide both sides by 5

y=7

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Looking at the set, we are given 18 elements. 17 is prime; it has only two factors: 1 and 17, since 1•17=17. So, the question is really asking what is the probability the numbers 1 or 17 is chosen. As mentioned earlier, 17 is prime, so there are two possible choices: 1 and 17.

P (probability) = possible outcomes / total outcomes

It is important to note that these events are “or” events, meaning that the probability can only be determined by choosing a 1 or a 17; you can’t randomly chose a 1 and 17 at the same time. So, the formula is:

P(A or B) = P(A) + P(B)

All this is saying is that given two possible outcomes, the probability occurs independent of each event; they don’t occur at the same time.

P(1 or 17) = P(1)/18 + P(1)/18

P(1 or 17) = 2/18

Since 17 is prime, it’s two and only factors are 1 and 17. The probability of randomly choosing a 1 or 17 is 2/18, meaning that there are 2 elements in the set out of a possible 18 elements that can be randomly chosen.

2/18 simplifies to 1/9


So, your answer is 1/9
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