Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identities
• 1 + cot² x = csc²x and csc x = 
• sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x
Consider the left side
sin²Θ( 1 + cot²Θ )
= sin²Θ × csc²Θ
= sin²Θ × 1 / sin²Θ = 1 = right side ⇔ verified
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Consider the left side
cos²Θ - sin²Θ
= cos²Θ - (1 - cos²Θ)
= cos²Θ - 1 + cos²Θ
= 2cos²Θ - 1 = right side ⇒ verified
I want to say the answer is A i caulated it and i end up getting 17
G should be the correct answer
Hope this helps!
Answer:
448 is the answer to 16y2 – 64.
Part A
Given that

Then,

For

, then

Thus,

For

, we have

Part B
Recall that from part A,

Now, at initial position, t = 0 and

, thus we have

and when the velocity drops to half its value,

and

Thus,

Thus, the distance the particle moved from its initial position to when its velocity drops to half its initial value is given by