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Alex_Xolod [135]
2 years ago
12

The length of a rectangle is 2 foot less than 3 times its width. Find the the dimensions of this rectangle if the area is 96 squ

are feet.
Mathematics
1 answer:
Xelga [282]2 years ago
6 0
For example,area = a, length = l, width = w
First we write two equations. The easier equation is the area equation, which we know to be
a = l x w
So that the first equation is : 
<span>96 = l x w </span>

we make the second equation of the following statements :
<em>The length of a rectangle is 2 foot less than 3 times its width.</em>
<span>so it becomes :
l = 3w - 2
</span>
<span>To solve, we can use the substitution method. 
</span>
96 = l \times w\\96=(3w-2) \times w\\96=3w^{2}-2w\\3w^{2}-2w-96=0~~~~~~[now\ factor\ the\ equation]\\ (3w+16)(w-6)=0

3w+16=0\\3w=-16\\w= -\frac{16}{3}~~~~\Rightarrow~~~answer\ doesnt\ make\ sense\ , negative\ width.&#10;

w-6=0\\\boxed{w=6~~~~~~~\Rightarrow~~~~positive\ answer\ for\ width\ makes\ sense }&#10;

<span><em>So if our width is 6, Now substitute the value of w = 6 into equation 2 </em></span>

l=3w-2\\l=3(6)-2\\l=18-2\\l=16

So "w" = 6 and "l" = 16, and if we multiply them together, we get the correct area, 96. So our dimensions are 6 by 16.
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cestrela7 [59]
Number 3 is 5
And 4 is 100.8
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3 years ago
The answer please. (F-g)(-3)
ad-work [718]
There are two ways to do this
Method 1:

Find (f-g)(x) first
(f-g)(x) = f(x) - g(x)
(f-g)(x) = (5x^2+3) - (-2x+4)
(f-g)(x) = 5x^2+3+2x-4
(f-g)(x) = 5x^2+2x-1

Then plug in x = -3
(f-g)(-3) = 5(-3)^2+2(-3)-1
(f-g)(-3) = 5(9)+2(-3)-1
(f-g)(-3) = 45-6-1
(f-g)(-3) = 39-1
(f-g)(-3) = 38

-----------------------------------------

Method 2:

Find f(-3)
f(x) = 5x^2+3
f(-3) = 5(-3)^2+3
f(-3) = 5(9)+3
f(-3) = 45+3
f(-3) = 48

Find g(-3)
g(x) = -2x+4
g(-3) = -2(-3)+4
g(-3) = 6+4
g(-3) = 10

Subtract the two results
(f-g)(-3) = f(-3) - g(-3)
(f-g)(-3) = 48 - 10
(f-g)(-3) = 38

-----------------------------------------

Whichever method you pick, the answer is: 38

4 0
3 years ago
A School decides to organize field trips for all students. Tickets for first years were sold at GH¢0.40 per student and continui
Pepsi [2]

Answer:

60%

Step-by-step explanation:

You can solve this problem by setting up a system of equations.

Let's say that the number of tickets bought by students in the first year is x, and the number bought by continuing students is y. From there, you can set it up like this:

0.4x+0.2y=160

x+y=500

Now, you can multiply the first equation by 5 on both sides to get:

2x+y=800

Subtracting the second equation from the first equation now yields:

x=300

y=200

Since 300 of the 500 tickets bought were from the first year students, and 300/500 is 0.6, 60% of the students who bought the ticket were first year students. Hope this helps!

7 0
3 years ago
For the data set below, which of the following measures is greatest? (20, 25, 30, 31, 32, 45, 45, 80). I will give 28 points!
shutvik [7]

Answer:

D.Mean

Step-by-step explanation:

3 0
3 years ago
Pls help stuck on big ideas math
beks73 [17]

Answer:

x = 15

Step-by-step explanation:

Substitute: -4/5x + 7 = -5

Rearrange unknown terms to the left side of the equation: -4/5x = -5 - 7

Calculate the sum or difference: -4/5x = -12

Divide both sides of the equation by the coefficient of variable: x = -12 × (-5/4)

Remove the parentheses: x = 12 × 5/4

Cross out the common factor: x = 3 × 5

Calculate the product or quotient: x = 15

So the answer is: x = 15

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2 years ago
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