(1/2)^2 = 1/4
2-2/3 = 6/3 - 2/3 = 4/3
OK so:
(1/2)^2 - 6(2-2/3) = 1/4 - 6(4/3)
= 1/4 - 8
= 1/4 - 32/4
= -31/4
Answer:
12
Step-by-step explanation:
This can be solved by working backwards.
7 is one more than half the number of invitations.
Subtract 1. 6 is half the number of invitations.
Double.
12 is the full number of invitations.
Algebra (if you must!):
x = number of invitations
x/2 + 1 = 7
Subtract 1.
x/2 = 6
Multiply by 2.
x = 12
Answer:
s = 21.16
Step-by-step explanation:
0.5s +1= 7+ 4.58
Combine like terms
0.5s +1=11.58
Subtract 1 from each side
0.5s +1-1= 11.58-1
.5s = 10.58
Multiply by 2
.5s *2 = 10.58*2
s = 21.16
<span>Carl has 3 bags in total. One backpack weighs 4 kg and the rest two checking bags have the equal weight. The total weight of 3 bags is given to be 35 kg.
Let the weight of each checking bag is w kg. So we can write:
2 x (Weight of a checking bag) + Weight of Backpack = 35
Using the values, we get:
2w+ 4 = 35
Using this equation we can find the weight of each checking bag, as shown below.
2w = 31
w = 31/2
w = 15.5
Thus, the weight of each checking bag is 15.5 kg
</span>
Answer:
Step-by-step explanation:
1 table and 2 chairs (2-seat table)
1 table and 4 chairs (4-seat table)
120 people so we need 120 chairs
Some Possibilities :
120 /4 = 30
0( 2-seat table) and 30 (4- seat tables) because 0·2 + 30·4 = 0+120 = 120
2( 2-seat table) and 29 (4- seat tables) because 2·2 + 29·4 = 4+ 116= 120
4( 2-seat table) and 28 (4- seat tables) because 4·2 + 28·4 = 8+ 112= 120
...
120/2 = 60
60( 2-seat table) and 0 (4- seat tables) because 60·2 + 0·4 = 120 + 0 = 120
58( 2-seat table) and 1 (4- seat tables) because 58·2 + 1·4 = 116 + 4 = 120
56( 2-seat table) and 2 (4- seat tables) because 56·2 + 2·4 = 112 + 8 = 120
...
