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3 years ago

Oduct of (x2 + 3)(x - 5).

Mathematics

1 answer:

Zanzabum3 years ago

8 0

Answer: 2x^2-7x-15

Step-by-step explanation:

reorder the terms (x*2+3)*(x-5)

multiply the parentheses

(2x+3)*(x-5)

collect like terms (2x^2-10x+3x-15)

product= 2x^2-7x-15

You might be interested in

Determine the measure of angle A, to the nearest degree.

Effectus [21]

Answer:

(a) 17°

(b) 78°

Step-by-step explanation:

(a) sin A= 0.2896

to calculate for "A" check for sin inverse of 0.2896

A= sin^-1(0.2896) = 16.83

to the nearest degree A= 17°

(b) tan A = 4.7046

A= tan^-1(4.7046)

A = 77.99

to the nearest degree A = 78°

4 0

2 years ago

With the beam being held still at a height of 40 m, the crane breaks and the beam falls to the ground. Assuming no air resistanc

lapo4ka [179]

What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.

Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy

TE = 0 + 0

∴ TE = 0

The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.

8 0

3 years ago

Write the equation of the line that passes through the points (2,−8) and (1,7). Put your answer in fully reduced point-slope for

ValentinkaMS [17]

Point-slope form of equation is: $y - 7 = -15(x-1)$

Step-by-step explanation:

Given points are:

(2,-8) and (1,7)

First of all we have to calculate the slope of the line

so,

$m=\frac{y_2-y_1}{x_2-x_1}\\= \frac{7-(-8)}{1-2}\\=\frac{7+8}{-1}\\=\frac{15}{-1}\\= -15$

Point-slope form is given by:

$y-y_1 = m(x-x_1)$

Putting the value of slope

$y-y_1 = -15(x-x_1)$

We can put any one of two given points in the equation to find the final form of point-slope form

Putting (1,7) in the equation

$y - 7 = -15(x-1)$

Hence, point-slope form of equation is: $y - 7 = -15(x-1)$

Reducing and simplifying

$y - 7 = -15(x-1)\\y-7 = -15x+15\\y-7+7 =-15x+15-7\\y = -15x+8\\15x+y = 8$

Keywords: Point-slope form, equation of line

Learn more about equation of line at:

#LearnwithBrainly

8 0

3 years ago

Which functions have graphs that are steeper than the graph of f(x)=−3x^2?

netineya [11]

Answer:

g(x)=−4x^2 and m(x)=4x^2

Step-by-step explanation:

A horizontal stretch or shrink happens when you multiply the parent function (in this case f(x) = x²) by a number. If this number is between 0 and 1, the graph will be stretched horizontally. If this number is greater than 1, the graph will be shrunk horizontally. If the number is between -1 and 0, the graph will be stretched horizontally and flipped; if the number is less than -1, the graph will be shrunk horizontally and flipped.

The graphs that are horizontally shrunk are steeper than the others. This is m(x)=4x^2 and g(x) = -4x^2.

8 0

3 years ago

A door of a lecture hall is in a parabolic shape. The door is 56 inches across at the bottom of the door and parallel to the flo

Arada [10]

Answer:

The parabolic shape of the door is represented by $y - 32 = -\frac{2}{49}\cdot x^{2}$ . (See attachment included below). Head must 15.652 inches away from the edge of the door.

Step-by-step explanation:

A parabola is represented by the following mathematical expression:

$y - k = C \cdot (x-h)^{2}$

Where:

$h$ - Horizontal component of the vertix, measured in inches.

$k$ - Vertical component of the vertix, measured in inches.

$C$ - Parabola constant, dimensionless. (Where vertix is an absolute maximum when $C < 0$ or an absolute minimum when $C > 0$ )

For the design of the door, the parabola must have an absolute maximum and x-intercepts must exist. The following information is required after considering symmetry:

$V (x,y) = (0, 32)$ (Vertix)

$A (x, y) = (-28, 0)$ (x-Intercept)

$B (x,y) = (28. 0)$ (x-Intercept)

The following equation are constructed from the definition of a parabola:

$0-32 = C \cdot (28 - 0)^{2}$

$-32 = 784\cdot C$

$C = -\frac{2}{49}$

The parabolic shape of the door is represented by $y - 32 = -\frac{2}{49}\cdot x^{2}$ . Now, the representation of the equation is included below as attachment.

At x = 0 inches and y = 22 inches, the distance from the edge of the door that head must observed to avoid being hit is:

$y -32 = -\frac{2}{49} \cdot x^{2}$