Yes, the sampling distribution is normally distributed because the population is normally distributed.
A sampling distribution is a chance distribution of a statistic obtained from a larger variety of samples drawn from a specific populace. The sampling distribution of a given population is the distribution of frequencies of a variety of various outcomes that would probable occur for a statistic of a populace.
A sampling distribution is a probability distribution of a statistic this is obtained via drawing a huge variety of samples from a particular populace. Researchers use sampling distributions so that you can simplify the technique of statistical inference.
Solution :
mean = μ40
standard deviation σ σ= 3
n = 10
μx = 40
σ x = σ√n = 3/√10 = 0.9487
μ x = 4σ\x = 0.9487
σx = 0.9487
Yes, the sampling distribution is normally distributed because the population is normally distributed.
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Step-by-step explanation:
1.
1% of 500 is 5 so multiply 5 by 8 for one year. which is 40 so multiply that by 2.
1% of 500 = 5
5 × 8 = 40
40 × 2 = 80
2.
1% of 1000 = 10
10 × 5 = 50
50 × 3 = 150
3.
12 months = 6%
6/12 = 1 month
0.5 = 1 month
0.5 × 9 = 4.5 (the amount of interest for 9 months.)
800 × 4.5% = 36
4.
12 months = 7%
7/12 = 1 month ( i'll leave this in fraction form because of the decimal points.)
7/12 x 8 = 4.666667 or 4.7 rounded.
1200 × 4.7% = 56.40
Answer:
Step-by-step explanation:
15*20=x
Answer:
The value of given log function is 1 .
Step-by-step explanation:
Given as :
Logb A = 3
Logb C = 2
Logb D = 5
<u>Now from log property </u>
if , Logb x = c , then x = 
So,
Logb A = 3 , then A = 
Logb C = 2 , then C = 
Logb D = 5 , then D = 
Now, According to question

So, 
Or, 
or, 
Now, since base same So,

∴ 
<u>Now log property </u>
= 1
Hence The value of given log function is 1 . answer
Answer:
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Step-by-step explanation: