1. Explain how you could break apart<br>an array to find 6 X 7. Draw an array<br>to show your work.

Which graph represents the sequence: 1/2, 1, 2, 4, 8...?

Aleonysh [2.5K]

The graph represents the sequence is Option D.

<h3>Further explanation </h3>

A function defined in the set of natural numbers is called a sequence.

Allow $\boxed{a_n \ as \ n^{th} \ term}$ , or general term.

In a sequence, n should always represent a natural number, i.e.,

n > 0, n = 1, 2, 3, ...,

but the value of $\boxed{a_n}$ may be any real number depending on the formula for the general term of the sequence.

A sequence is considered geometric if the ratio between each consecutive term is common.

In our problem, the sequence is $\boxed{ \ \frac{1}{2}, 1, 2, 4, 8, ... \ }$

The ratio of each term $\boxed{a_{n+1}}$ to the previous term $\boxed{a_n}$ is equal 2, so we can formalize the sequence as

$\boxed{\frac{a_{n+1}}{a_n} =2}.$

The consecutive terms of the sequence have a common ratio r = 2, so this sequence is geometric.

The general term of a geometric sequence $\boxed{a_n}$ with common ratio r is $\boxed{\boxed{ \ a_n = a_1 \cdot r^{n-1} \ }}.$

Presently we go back to the question. The graph shows the horizontal axis as n and the vertical axis is the general term $\boxed{a_n}$ . The relationship between n, the terms, and the coordinates as written below:

$\boxed{n = 1 \rightarrow the \ 1st \ term \ a_1 = \frac{1}{2} \rightarrow \bigg( 1, \frac{1}{2} \bigg)}$

$\boxed{n = 2 \rightarrow the \ 2nd \ term \ a_2 = 1 \rightarrow (2, 1)}$

$\boxed{n = 3 \rightarrow the \ 3rd \ term \ a_3 = 2 \rightarrow (3, 2)}$

$\boxed{n = 4 \rightarrow the \ 4th \ term \ a_4 = 4 \rightarrow (4, 4)}$

$\boxed{n = 5 \rightarrow the \ 5th \ term \ a_5 = 8 \rightarrow (5, 8)}$

Therefore, the graph representing the sequence is Option D.

The general term of a geometric sequence is exponential.
From the common ratio (r > 1) and graph, the type is an increasing sequence.

<h3>Learn more </h3>

Combining two functions to create a geometric sequence brainly.com/question/1695742
A word problem about arithmetic and geometric sequences brainly.com/question/3395975
Drawing graph of the geometric sequence brainly.com/question/3166290

Keywords: which, the graph, geometric sequences, common ratio, general term formula, natural numbers, The consecutive terms, arithmetic

6 0

3 years ago

Suppose monthly rental prices for a one-bedroom apartment in a large city has a distribution that is skewed to the right with a

omeli [17]

Answer:

a) Nothing, beause the distribution of the monthly rental prices are not normal.

b) 1.43% probability that the sample mean rent price will be greater than $900

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

(a) Suppose a one-bedroom rental listing in this large city is selected at random. What can be said about the probability that the listed rent price will be at least $930?

Nothing, beause the distribution of the monthly rental prices are not normal.

(b) Suppose a random sample 30 one-bedroom rental listing in this large city will be selected, the rent price will be recorded for each listing, and the sample mean rent price will be computed. What can be said about the probability that the sample mean rent price will be greater than $900?

Now we can apply the Central Limit Theorem.

$\mu = 880, \sigma = 50, n = 30, s = \frac{50}{\sqrt{30}} = 9.1287$

This probability is 1 subtracted by the pvalue of Z when X = 900.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{900 - 880}{9.1287}$

$Z = 2.19$

$Z = 2.19$ has a pvalue of 0.9857

1 - 0.9857 = 0.0143

1.43% probability that the sample mean rent price will be greater than $900

8 0

3 years ago

Only two problems I don’t understand. Don’t just give me answer, explain too please.

marta [7]

Answer:

12. Option b: 20 is the correct answer.

13. Option a: A rose costs $1 more than a daisy is the correct answer.

Step-by-step explanation:

12. Given that:

15x+10y=700 Eqn 1

x+y=60 Eqn 2

To find x, we will eliminate y be multiplying Eqn 2 by 10

10(x+y=60)

10x+10y=600 Eqn 3

Subtracting Eqn 3 from Eqn 2

(15x+10y)-(10x+10y)=700-600

15x+10y-10x-10y=100

5x=100

Dividing both sides by 5

$\frac{5x}{5}=\frac{100}{5}\\x=20$

Hence,

Option b: 20 is the correct answer.

13. Given that:

5x+4y=32 Eqn 1

x+6y=22 Eqn 2

Multiplying Eqn 2 by 5

5(x+6y=22)

5x+30y=110 Eqn 3

Subtracting Eqn 1 from Eqn 3

(5x+30y)-(5x+4y)=110-32

5x+30y-5x+4y=78

26y=78

Dividing both sides by 26

$\frac{26y}{26}=\frac{78}{26}\\y=3$

Putting y=3 in Eqn 2

x+6(3)=22

x+18=22

x=22-18

x=4

Hence,

Option a: A rose costs $1 more than a daisy is the correct answer.

7 0

3 years ago

Latex- free gloves can be purchased in a box of 100 for $44.95 or a box of 50 for $23.50. Which one would be the best deal

malfutka [58]

The box of 100 would be the better deal, considering buying 2 boxes of 50 would turn out to be $47.00

3 0

3 years ago

Read 2 more answers

This graph shows the cost of a small cheese pizza at 3 different restaurants. a) explain how the size of the bars gives a false

nlexa [21]

I would answer, but I don’t see the graph. If you add the graph I could help (if you want of course, not trying to be rude. Sorry!)

8 0

3 years ago

1. Explain how you could break apartan array to find 6 X 7. Draw an arrayto show your work.​

1. Explain how you could break apartan array to find 6 X 7. Draw an arrayto show your work.