Eliminate p :
2 (m + 2n + 2p) + (-1) (3m - n + 4p) = 2 (4) + (-1) 25
2m + 4n + 4p - 3m + n - 4p = 8 - 25
-m + 5n = -17
(m + 2n + 2p) + 2 (3m + 2n - p) = 4 + 2 (-4)
m + 2n + 2p + 6m + 4n - 2p = 4 - 8
7m + 6n = -4
Eliminate m :
7 (-m + 5n) + (7m + 6n) = 7 (-17) + (-4)
-7m + 35n + 7m + 6n = -119 - 4
41n = -123
Solve for n :
n = -3
Solve for m :
-m + 5 (-3) = -17
-m - 15 = -17
m = 2
Solve for p :
2 + 2 (-3) + 2p = 4
2 - 6 + 2p = 4
2p = 8
p = 4
The student used the wrong trig ratio. They should use cosine instead.

If the student wanted to use sine, then they would need to use the pythagorean theorem to find the opposite side first. I recommend using cosine since it's faster. Make sure your calculator is in degree mode.
Answer: how come you don't know the answer what grade are you in