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Usimov [2.4K]
3 years ago
14

What is the arc measure of \stackrel{\LARGE{\frown}}{AB}

Mathematics
2 answers:
vova2212 [387]3 years ago
3 0

Answer:

72 degrees

Step-by-step explanation:

Find the diagram attached. We are to find the length of the arc

Measure of arcABC = rtheta

16π = 10 theta

theta  = 16*180/10

theta = 16 * 18

theta = 288degrees

central angle = 360 - 288 = arc AC

central angle = 72degrees

Hence the arc measure of AC is 72 degrees

Montano1993 [528]3 years ago
3 0

Answer:

72

Step-by-step explanation:

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KLMN is a parallelogram,
Aleonysh [2.5K]

Answer:

Ok soo.

Step-by-step explanation:

sum of two adjacent angles of parallelogram is 180

so angle K + angle L = 180

as AK bisects angle K and LA bisects angle L

so, angle AKL + angle ALK = 180 /2 = 90

in triangle AKL,

angle AKL + angle ALK+angle KAL = 180(sum of all angles in triangle = 180)

so, from above two equations,

angle KAL = 90

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4 0
3 years ago
Solve for f is h=2f/m+1
Natasha_Volkova [10]
H=2f/m+1
subtract one from both sides
h-1=2f/m
multiply m to both sides
m*h-1=2f
divide 2 both sides
mh-1/2=F
<span>(the whole left side of the equation is divided by 2 i just cant do it on the computer)</span>
7 0
3 years ago
The weight of a small bag of raisins of 3.0 times the weight of a large bag. The large bag weight 8.0 of a pound. what is the we
Viefleur [7K]

Answer:

4/15

Step-by-step explanation:

7 0
2 years ago
The shoe store expected to sell at least 95 pairs of shoes one weekend, but they only sold 77 pairs. What was the approximate pe
Gwar [14]
The error of percentage is the amount of error over the original amount.

In this case it is 22/95  (not 22 over 77 because 77 is not the original amount they expected to sell.   

22/95 = .2315  or 23.2% to the nearest tenth of a percent
Perhaps your teacher just wants 23% as an the approximate error.
7 0
3 years ago
Read 2 more answers
A certain medical test is known to detect 73% of the people who are afflicted with the disease Y. If 10 people with the disease
Setler [38]

The probability of an event is the measurement of the chance of that event's occurrence. The probabilities of considered events are:

  • P(At least 8 have the disease) ≈ 0.4378
  • P(At most 4 have the disease)  ≈ 0.0342
<h3 /><h3>How to find that a given condition can be modeled by binomial distribution?</h3>

Binomial distributions consist of n independent Bernoulli trials. Bernoulli trials are those trials that end up randomly either on success (with probability p) or on failures( with probability 1- p = q (say))

Suppose we have random variable X pertaining to a binomial distribution with parameters n and p, then it is written as

X = B(n,p)

The probability that out of n trials, there'd be x successes is given by

P(X=x)  = ^nC_xp^x(1-p)^{n-x}

Since 10 people can be either diseased or not and they be so independent of each other (assuming them to be selected randomly) , thus, we can take them being diseased or not as outputs of 10 independent Bernoulli trials.

Let we say

Success= Probability of a diseased person tagged as diseased by the clinic

Failure = Probability of a diseased person tagged as not diseased by the clinic.

Then,

P(Success) = p = 72% = 0.72 (of a single person)

P(Failure) = q = 1-p = 0.28

Let X be the number of people diagnosed diseased by the clinic out of 10 diseased people. Then we have: X ≈ B(n+10,P=0.73)

Calculating the needed probabilities, we get:

a) P(At leased 8 have disease) = P(X≥8) =P(X=8) + P(X=9) + P(X=10)

P(X≥8) = ^{10}C_8(0.73)^8(0.28)^2+^{10}C_9(0.73)^9(0.27)^1+^{10}C_{10}(0.73)^{10}(0.27)^0

P(X≥8) ≈ 0.2548 + 0.1456 + 0.0374 ≈ 0.4378

b)  P(At most 4 have the disease) = P(X≤4) = P(X=0) + P(X=1)+P(X=2)+P(X=3)+P(X=4)

P (X ≤ 4) =

^{10}C_0(0.73)^0(0.27)^{10}+^{10}{C_1(0.73)^1(0.27)^9+^{10}{C_2(0.73)^2(0.27)^8+^{10}C_3(0.73)&^3(0.27)^7 \\

+^{10}C_4(0.73)^4(0.27)^6

P (X ≤ 4) = 0.000003 + 0.000076+0.00088+0.00604+0.02719

P (X ≤ 4) =  0.0342

Thus,

The probabilities of considered events are:

  • P(At leased 8 have disease) = 0.4378 approx
  • P(At most 4 have the disease)  = 0.0342 approx

Learn more about binomial distribution here:

brainly.com/question/13609688

#SPJ1

4 0
2 years ago
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