Question

What is the equation of a line that contains the points (2,-2) and (0, -2)?

Answer 1

$\text{Hey there!}$

$\text{The equation is: }\dfrac{\text{y}_2 -\text{y}_1}{\text{x}_2-\text{x}_1}$

$\text{y}_2 = -2\\\text{y}_1=-2\\\text{x}_2=0\\\text{x}_1=2$

$\dfrac{-2 - (-2)}{0-2}$

$\bf{-2 - (-2)= -2 + 2 \rightarrow0}$

$\dfrac{0}{0-2}$

$\bf{0 - 2 = -2}$

$\dfrac{0\leftarrow\text{y-intercept}}{-2\leftarrow\text{x-intercept}}$

• $\boxed{\text{Answer \#1: y = 0}}$ $\checkmark$
• $\boxed{\text{Answer \# 2: x = -2}}$ $\checkmark$
• $\boxed{\text{Overall answer: -2}}$

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Answer 2

Answer:

y = - 2

Step-by-step explanation:

The equation of a horizontal line parallel to the x- axis is

y = c

Where c is the value of the y- coordinates the line passes through

The line passes through (2, - 2) and (0, - 2) both with y- coordinate of - 2, thus

Equation of line is y = - 2