Answer:
3y3(x2 + 4)(x + 2)(x -2)
Step-by-step explanation:
3x4y3– 48y3.
= 3y3(x4 – 16).
= 3y3[(x2)2 - 42].
= 3y3(x2 + 4)(x2 - 4).
= 3y3(x2 + 4)(x2 - 22).
= 3y3(x2 + 4)(x + 2)(x -2).
the domain of f(x)= x2 +1 is limited to {0,1,2,3)
the maximum value will be at the maximum value of x which is at x = 3
So, the maximum value of the range will be = 3^2 + 1 = 9 + 1 = 10
Answer:
0.027777778
Step-by-step explanation:
40,978 would be the answer hope it helped!
20& 10/35 - 26/35
19& 16/35 simplified to it's fullest.