Complete Question
According to the Bureau of Labor Statistics, citizens remain unemployed for an average of 15.9 weeks before finding their next job (June, 2008). Suppose you want to show that Louisiana has been effective in getting their unemployed back to work sooner. You take a random sample of 50 citizens who were unemployed six months earlier and ask them to report the duration. You find that the average time spent unemployed was 13.4 weeks with a sample standard deviation of the time unemployed is 6.7 weeks.
1 Which of the following statements is the correct alternative hypothesis?
2 The test statistic for testing the hypothesis is
a. -2.64
b. -2.32
c. -2.11
d. -1.28
e. none of these are correct
Answer:
1
The alternative hypothesis 
2
The test statistics
Step-by-step explanation:
From the question we are told that
The population mean value for time citizens remain unemployed is 
The sample size is n = 50
The sample standard deviation is 6.7 weeks.
The sample mean value for time citizens remain unemployed is 
The null hypothesis is 
The alternative hypothesis 
Generally test statistics is mathematically represented as
=> 
=>
Answer:
First do the Base multiplied by the Height.
After divide by 2
Step-by-step explanation:
Answer: 50 ft
Step-by-step explanation:
The correct function is h(t)=-16t^2+200t+50.
Hi, to answer this question we simply have to replace t =0 in the function given:
h(t)=-16t^2+200t+50.
h (0) = -16t^2+200t+50.
h(0) = 50
When the time is 0, the rocket is at the top of the building.
The rocket was launched from a 50 ft height.
Feel free to ask for more if needed or if you did not understand something.
To determine the correct statement in the choices presented, we first have to solve the area of the tray. We assume it to be in a rectangular form so the area is:
Area = 10 in x 10 in x 7/2.54 in = 275.59 in³ for the paint tray
1 gallon paint = 231 in³ paint
Therefore, the correct answer is the first option. <span>The paint will not fill the tray by 44.59 in</span>³<span>.</span>
Any fraction that does not equal 1/2.