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Anni [7]
3 years ago
15

.428571429 as a fraction

Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
5 0
Answer is 42/100 is the answer
kap26 [50]3 years ago
5 0
\frac{3}{7} \approx .\overline{428571}

Or just what the question specifies:

\frac{428571429}{1000000000} = .428571429
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Let U={q, r, s, t, u, V, W, X, Y, Z},
trapecia [35]

Answer:

Ooh is theis unions I did it but

3 0
2 years ago
Please answer this question with explantion.<br> -35 × -98
beks73 [17]
A positive 3430. because two negatives that are being multiplied by eachother are automatically positive.
3 0
3 years ago
The histogram shows the number of yards gained on first downs. How many times did the team gain at least 6 yards on first downs?
BabaBlast [244]

Answer:

8 times

Step-by-step explanation:

Given

The attached histogram

Required

The number of times the team gain at least 6 yards

From the question, the entry that fall in the category of at least 6 yards are:

6\ to\ 8, 9\ to\ 11 and 12\ to\ 14

Their frequencies are:

5, 2 and 1 respectively

So, the number of times is:

Times = 5 + 2 + 1

Times =8

4 0
3 years ago
Read 2 more answers
If g(x)=3x-1 and if g(a)=7 what is the value of a?
Ierofanga [76]

Answer:

a = 8/3

Step-by-step explanation:

3a - 1 would equal 7

3a = 7 + 1

3a = 8

a = 8/3

6 0
3 years ago
Use the equation a = IaIâ
german

Answer:

a) \:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b)\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) \:\:=7\cdot \frac{\:\:}{7}

Step-by-step explanation:

a) Let <u>a</u>=<2,1,-3>

The magnitude of <u>a</u> is |a|=\sqrt{2^2+1^2+(-3)^2}

|a|=\sqrt{4+1+9}=\sqrt{14}

The unit vector in the direction of a is

\hat{a}=\frac{\:\:}{\sqrt{14} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b) Let a=2i - 3j + 4k

|a|=\sqrt{2^2+(-3)^2+4^2}

|a|=\sqrt{4+9+16}=\sqrt{29}

\hat{a}=\frac{\:\:}{\sqrt{29} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) Let us first find the sum of <1, 2, -3> and <2, 4, 1> to get:

<1+2, 2+4, -3+1>=<3, 6, -2>

Let a=<3, 6, -2>

The magnitude is

|a|=\sqrt{3^2+6^2+(-2)^2}

|a|=\sqrt{9+36+4}=\sqrt{49}=7

The unit vector in the direction of <u>a</u> is

\hat{a}=\frac{\:\:}{7}

Using the relation a=|a|\hat{a}, we have

\:\:=7\cdot \frac{\:\:}{7}

5 0
3 years ago
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