All categories

2 years ago

What number when added to 13 gives 2?

Mathematics

2 answers:

Kruka [31]2 years ago

7 0

The answer is -11
so the equation would be 13+(-11)=2

jok3333 [9.3K]2 years ago

7 0

Answer -11
Explanation. -11+13= 2. 13-11=2

You might be interested in

What is the value of y¹ when y = 5 and x - 10?

Mrrafil [7]

Answer:

Step-by-step explanation:

y^1 = 5^1 (y = 5)

Anything raised to the power of 1 is just itself.

So, 5^1 = 5

8 0

1 year ago

What value is true of x makes this equation true 0.7x-5=0.2x+1

Sever21 [200]

Answer:

x=12

Step-by-step explanation:

First you make sure x is on both sides of the equation. So you do 0.7x-5-0.2x=0.2x+1-0.2x. Which just simplifies to 0.5x-5=1. You make sure x is the only thing on that side of the equation so you do 0.5x-5+5=1+5 which simplifies to 0.5x=6. Multiply the equation times 2 to just have x. x=12. The value that makes true of x is 12.

7 0

3 years ago

Choose the equation that best represents the general form of the following expression. x^2/2=7x user: what is the value of "c" i

AlexFokin [52]

X^2/2 = 7x
x^2 = 14x
x^2 - 14x = 0

A quadratic equation is of the form ax^2 + bx + c
Therefore, in 3x^2 + 5x + 7, c = 7

4 0

2 years ago

Why did you multiply 15 by 3?

navik [9.2K]

To get an answer which is....45

8 0

3 years ago

Read 2 more answers

On the 1st January 2014 Carol invested some money in a bank account.

Ghella [55]

Answer:

$\large \boxed{\text{\pounds 23 360.00}}$

Step-by-step explanation:

The formula for the accrued amount from compound interest is

$A = P \left(1 + \dfrac{r}{n}\right)^{nt}$

1. Amount in account on 1 Jan 2015

(a) Data:

a = £23 517.60

r = 2.5 %

n = 1

t = 1 yr

(b) Calculations:

r = 0.025

$\begin{array}{rcl}23517.60 & = & P\left (1 + \dfrac{r}{n}\right)^{nt}\\\\& = & P\left (1 + \dfrac{0.025}{1}\right)^{1\times1}\\\\& = & P (1 + 0.025)\\ & = & 1.025 P\\P & = & \dfrac{23517.60 }{1.025} \\\\& = & 22 944.00 \\\end{array}$

The amount that gathered interest was £22 944.00 but, before the interest started accruing, Carol had withdrawn £1000 from the account.

She must have had £23 944 in her account on 1 Jan 2015.

(2) Amount originally invested

(a) Data

A = £23 944.00

$\begin{array}{rcl}23 944.00 & = & 1.025 P\\P & = & \dfrac{23 944.00 }{1.025} \\\\& = & \mathbf{23 360.00} \\\end{array}\\\text{Carol originally invested $\large \boxed{\textbf{\pounds23 360.00}}$ in her account.}$

3. Summary

1 Jan 2014 P = £23 360.00

1 Jan 2015 A = 23 944.00

Withdrawal = <u> -1 000.00 </u>

P = 22 944.00

1 Jan 2016 A = £23 517.60

5 0

3 years ago

What number when added to 13 gives 2?​

What number when added to 13 gives 2?