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Sati [7]
2 years ago
13

The apr of deloris' savings account is 3.8%, and interest is compounded semiannually. if the principal in deloris' savings accou

nt were $13,700 for an entire year, what would be the balance of her account after all the interest is paid for the year?
Business
2 answers:
SashulF [63]2 years ago
5 0

Answer:

Deloris' account balance would be $14,225.55 after one year.

Explanation:

The formula FV=PV(1+\frac{r}{n})^{nt} is used to find compound interest.

FV = result or final amount

PV = starting or principal amount

r = annual interest rate (as a fraction)

n = number of compounds a year (semiannually is 2, quarterly is 4...)

t = number of years

Now we can plug and solve:

FV=13,700(1+\frac{0.038}{2})^{2(1)} = 13,700(1+0.019)^2 = 13,700(1.019)^2 = 13,700(1.038361)

= $14,225.55

Alex Ar [27]2 years ago
3 0
The future value of the balance in a savings account, PV, with an apr of r% compounded t times a year for n years is given by:

FV=PV\left(1+ \frac{r}{t} \right)^{nt}

Given that t<span>he apr of deloris' savings account is 3.8%, and interest is compounded semiannually. if the principal in deloris' savings account were $13,700 for an entire year, the balance of her account after all the interest is paid for the year is given by

FV=13,700\left(1+ \frac{0.038}{12} \right)^{12\times1} \\  \\ 13,700(1+ 0.0032)^{12}=13,700(1.0032)^{12} \\  \\ 13,700(1.0387)=\bold{\$14,229.76}</span>
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Answer:

Given,

Annual demand, D = 12500,

Setting up cost, S = $ 49,

Production rate per year, P =  production facility × capability of production = 300 × 105 = 31500,

Holding cost per year, H = $ 0.15,

Hence,

(i) Optimal size of the production run,

Q = \sqrt{\frac{2DS}{H(1-\frac{D}{P})}}=\sqrt{\frac{2\times 12500\times 49}{0.15(1-\frac{12500}{31500})}}=3679.60238126\approx 3680

(ii) Average holding cost per year,

=\frac{QH}{2}(1-\frac{D}{P})

=\frac{3680\times 0.15}{2}(1-\frac{12500}{31500})

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(iii) Average setup cost per year,

=\frac{D}{Q}\times S

=\frac{12500}{3680}\times 49

=166.44021739

\approx \$ 166.44

(iv) Total cost per year = average setup cost per year + average holding cost per year + cost to purchase 12500 lights

= 166.44 + 166.48 + 12500(0.95)

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7 0
3 years ago
Gleason Company reported net income of $242,000 for the year. During the year, accounts receivable increased by $32,000, account
Degger [83]

Net cash provided by operating activities for the year is $265,000. $102,000. $242,000. $337,000 is :- <u>$265,000</u>

What is depreciation expense?

A fixed asset's share that has been deemed consumed in the current period is subject to depreciation expense. The cost is subsequently added to the expense list. With this charge, the carrying amount of fixed assets will be steadily decreased as their value is depleted over time. There is no cash outflow related to this item because it is non-monetary.

When an entry is made to the depreciation expenditure account, the contra asset account that offsets the fixed assets (asset) account is the accumulated depreciation account. Over the course of a fiscal year, the balance in the depreciation expenditure account grows; at year's end, the account is flushed out and its balance is reset to zero.

To learn more about depreciation expense with the help of given link:

brainly.com/question/25530648

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1 year ago
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Phil purchased a car today at a price of $8,500. He paid $300 down in cash and financed the balance for 36 months at 5.75 percen
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Answer:

\large\boxed{\large\boxed{\$ 248.53}}

Explanation:

The equation to calculate the <em>monthly payment</em> for fixed-rate loans is:

     Monthly\text{ }payment=Loan\times \bigg[\dfrac{r(1+r)^t}{(1+r)^t-1}\bigg]

Where:

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Substituting:

Monthly\text{ }payment=\$8,200\times \bigg[\dfrac{(0.0575/12)(1+(0.0575/12))^{36}}{(1+(0.0575/12))^{36}-1}\bigg]=\$ 248.53

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Answer:

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