3 years ago

What is the vertex of f(x)=5^2+20-16

1 answer:

4 0

The given equation is f(x) = 29. The graph is a horizontal line, which has no vertex. Perhaps you intend
.. f(x) = 5x^2 +20x -16
.. = 5(x^2 +4x +4) -16 -20
.. = 5(x +2)^2 -36

The vertex is (-2, -36)

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aev [14]

Answer:

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Step-by-step explanation:

2(|x+4|+3)=6

take out absolute value

2(x+4+3)=6

remove parrenthesis

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Hope this helps!!!!!

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3 years ago

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312/17
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GrogVix [38]

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