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xxTIMURxx [149]
3 years ago
5

please solve the question is this 176 x 17 and 180 x 20 = 3600 overestimated or underestimated a. overestimated or b. underestim

ated make sure u show me why its the right answer and where your answer from
Mathematics
1 answer:
Citrus2011 [14]3 years ago
4 0
176 rounds up to 180
17 rounds up to 20
The fact we're rounding up both times means we'll have an overestimate
estimate = 180*20 = 3600
actual result = 176*17 = 2992
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Can someone please give me the answer to these two?
Radda [10]

Answer:

3: D - Undefined

4: A - 1

Step-by-step explanation:

For Question 3 your answer is D, undefined, because it does not have a slope, a slope is like a hill, but that just goes straight up, thus it is undefined.

For Question 4 your answer is A, 1, because it moves one digit to the right and then 1 digit up, Thus that is your answer.

6 0
3 years ago
Given: f(x) = 2x-1 and g(x) = 2x-3<br> Find:<br> (fog)(x)<br> HELP PLEASEE!!
Murljashka [212]

Answer:

(fog)(x) = 4x - 7

Step-by-step explanation:

f(x) = 2x-1 and g(x) = 2x-3;

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7 0
3 years ago
Help!<br><br> Please look at the pic and help me!
inna [77]

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5 0
3 years ago
Read 2 more answers
XY is a diameter of a circle and Z is a point on the circle such that ZY=6. If the area of the triangle XYZ is 18 square root 3
nataly862011 [7]
<h2>Answer:</h2>

4π

<h2>Step-by-step explanation:</h2>

As shown in the diagram, triangle XYZ is a right triangle. Therefore, its area (A) is given by:

A = \frac{1}{2} x b x h      -------------(i)

Where;

A = 18\sqrt{3}

b = XZ = base of the triangle

h = YZ = height of the triangle = 6

<em>Substitute these values into equation(i) and solve as follows:</em>

18\sqrt{3} =  \frac{1}{2} x b x 6

18\sqrt{3} =  3b

<em>Divide through by 3</em>

6\sqrt{3} =  b

Therefore, b = XZ = 6\sqrt{3}

<em>Now, assume that the circle is centered at O;</em>

Triangle XOZ is isosceles, therefore the following are true;

(i) |OZ| = |OX|

(ii) XZO = ZXO = 30°

(iii) XOZ + XZO + ZXO = 180°   [sum of angles in a triangle]

=>  XOZ + 30° + 30° = 180°

=>  XOZ + 60° = 180°

=>  XOZ = 180° - 60°

=>  XOZ = 120°

Therefore we can calculate the radius |OZ| of the circle using sine rule as follows;

\frac{sin|XOZ|}{XZ} = \frac{sin|ZXO|}{OZ}

\frac{sin120}{6\sqrt{3} } = \frac{sin 30}{OZ}

\frac{\sqrt{3} /2}{6\sqrt{3} } = \frac{1/2}{|OZ|}

\frac{1}{12}  = \frac{1}{2|OZ|}

\frac{1}{6} = \frac{1}{|OZ|}

|OZ| = 6

The radius of the circle is therefore 6.

<em>Now, let's calculate the length of the arc XZ</em>

The length(L) of an arc is given by;

L = θ / 360 x 2 π r          ------------------(ii)

Where;

θ = angle subtended by the arc at the center.

r = radius of the circle.

In our case,

θ = ZOX = 120°

r = |OZ| = 6

Substitute these values into equation (ii) as follows;

L = 120/360 x 2π x 6

L = 4π

Therefore the length of the arc XZ is 4π

5 0
3 years ago
Rename the fraction as a percent:1/2 =
Charra [1.4K]
1/2 = 0.5...to turn to a percent, multiply by 100.
0.5 x 100 = 50%
7 0
3 years ago
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