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3 years ago

Find the value of the variable if P is between J&K JP=8z-17; PK=5z+37; JK=17z-4

1 answer:

5 0

Because P it between J and K it means that JP+PK = JK. That means:
8z-17+5z+37=17z-4
13z+20=17z-4
4z=24
z=6

The value of the variable is 6.

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4x + 2 < −2 OR 4x + 2 > 26 solve pl

inn [45]

Step-by-step explanation:

The easiest thing to do here is:

4x + 2 = -2 and 4x + 2 = 26

Just know whaever you get for x is greater or less than the actual answer.

4x + 2 = -2

- 2 - 2

4x = -4

$\frac{4x}{4} = \frac{-4}{4}$

x = -1 <--- Because -2 is supposed to be greater than x, x equals any number less than -1 but not -1.

4x + 2 = 26

- 2 - 2

4x = 24

$\frac{4x}{4} = \frac{24}{4}$

x = 6 <--- Because 26 is supposed to be less than x, x equals any numbey greater than 6 but not 6

6 0

3 years ago

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taurus [48]

15/2 r -40, the first answer

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3 years ago

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Delvig [45]

Number of chores is independent, the other is dependent

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3 years ago

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Find the measure of the the sides of DEF then classify it by it sides. D(8,-6) E(-1,-3) F(-2,5)

Mama L [17]

Answer:

Part a) The measure of the sides of triangle DEF are

$d_D_E=\sqrt{90}\ units$

$d_E_F=\sqrt{65}\ units$

$d_D_F=\sqrt{221}\ units$

Part b) Is a scalene triangle

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have the coordinates

D(8,-6) E(-1,-3) F(-2,5)

step 1

Find the length side DE

D(8,-6) E(-1,-3)

substitute in the formula

$d=\sqrt{(-3+6)^{2}+(-1-8)^{2}}$

$d=\sqrt{(3)^{2}+(9)^{2}}$

$d_D_E=\sqrt{90}\ units$

step 2

Find the length side EF

E(-1,-3) F(-2,5)

substitute in the formula

$d=\sqrt{(5+3)^{2}+(-2+1)^{2}}$

$d=\sqrt{(8)^{2}+(-1)^{2}}$

$d_E_F=\sqrt{65}\ units$

step 3

Find the length side DF

D(8,-6) F(-2,5)

substitute in the formula

$d=\sqrt{(5+6)^{2}+(-2-8)^{2}}$

$d=\sqrt{(11)^{2}+(-10)^{2}}$

$d_D_F=\sqrt{221}\ units$

step 4

Classify the triangle by the measure of its sides

we have

$d_D_E=\sqrt{90}\ units$

$d_E_F=\sqrt{65}\ units$

$d_D_F=\sqrt{221}\ units$

Is a scalene triangle, because is a triangle in which all three sides have different lengths.

6 0

3 years ago

Will side lengths of 3 cm, 4 cm, and 5 cm form a triangle? explain.

Gelneren [198K]

Yes, that is the famous first Pythagorean triplet: 3²+4²=5²

For three lengths to be able to form a triangle, it suffices that every one of those lengths is shorter than the sum and longer than the difference of the other two.

It is enough to check just one side.

So,

3 + 4 > 5

4 - 3 < 5

Your triangle is constructible.

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3 years ago

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