Question

A rectangular city lot has an area of 1000 square meters. If the length of the lot is 10 meters more than twice its width, find its length and width.

Answer 1

Answer: l=50 m, w=20 m

Step-by-step explanation:

Given

A rectangular city has an area of $1000\ m^2$

Also, length is 10 m more than twice its width

suppose width is w

So, length is given by

$\Rightarrow l=10+2w$

The area is given by

$\Rightarrow A=l\times w\\\Rightarrow 1000=(10+2w)\times w\\\Rightarrow 2w^2+10w-1000=0\\\Rightarrow w^2+5w-500=0\\\Rightarrow w^2+25w-20w-500=0\\\Rightarrow (w+25)(w-20)=0\\\therefore w=20\ m\\l=10+2w=10+2\times 20=50\ m$