Use the factor theorem to determine whether the first polynomial is a factor of the second polynomial x-3;2x^2-4x+30
x−3,2x^2−4x+30
Answer:
This question is incomplete
Answer:
Step-by-step explanation:
1. There are only 4 numbers including 5 that follow the "five or more" requirment, and the probability of spinning it once is 4/8, or 1/2. (The total sections is 8) Then we multiply 1/2 and 1/2 together to get the "two times in a row" requirement done. (1/2)*(1/2)= 1/4 is the probability.
2. There are two values on the spinner that are a multiple of 3, 3 itself and 6. Again, the total amount of numbers/sections is 8, so the probability of spinning a multiple of three is 2/8 or 1/4. The probability of spinning an odd number is 4/8 or 1/2. (1/2)*(1/4)=1/8 is the probability.
3. The probability of spinning one odd number is 1/2, and so we multiply 1/2 by itself four times. (1/2)*(1/2)*(1/2)*(1/2)=1/16 is the probability.
4. There are 6 numbers greater than two on the number wheel not including two itself. So the probability of that is 6/8, or 3/4. Then we multiply 3/4 by itself 3 times as it asks. (3/4)*(3/4)*(3/4)*(3/4)=81/256 is the probability.
Note that I am not really sure about the answer myself, but I hope that this can help in some way. Good luck! :)
3.33333333 as a whole number is 3
You haven't provided the expression or the choices, therefore, I cannot provide an exact answer.
However, I'll try to help you understand the concept so that you can solve the question you have
Like radicals are characterized by the following:1- They both have the same root number (square root, cubic root , ...etc)
2- They both have the same radicand (meaning that the expression under the root is the same in both radicals)
Examples of like radicals:3

and 7

![\sqrt[5]{x^2y}](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7Bx%5E2y%7D%20)
and 3
![\sqrt[5]{x^2y}](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7Bx%5E2y%7D%20)
Check the choices you have. The one that satisfies the above two conditions would be your correct choice
Hope this helps :)