The first one.
This statement is saying that x is less than zero and greater than zero at the same time. This is not possible. A number cannot be both negative and positive.
It's not the second one because this one includes equal to zero. It can be lass than or equal to zero and greater that or equal to zero because it can be ZERO.
It's not the third because this one is an OR statement. It can be less than or equal to zero OR greater than or equal to zero.
I hope you understand
Answer:
50°
Step-by-step explanation:
In a parallelogram, opposing angles must be equal. Note how 75° = 75°. Thus, opposing angles 2x + 5 and x + 55 must also be equal.
Solve this equation for x.
Subtracting x from both sides yields x + 5 = 55. Next: Subtracting 5 from both sides yields x = 50° (answer choice C)
Answer: 4x² + 4x - 2 - 
<u>Step-by-step explanation:</u>
You can use either synthetic or long division. I am using synthetic division:
2x + 3 = 0 ⇒ x = 
| 4 10 4 -6
<u>| ↓ -6 -6 3 </u>
4 4 -2 -3 ← <em>-3 is the remainder</em>
↓ ↓ ↓
4x² +4x -2 ← <em>factored polynomial</em>
Answer:
∠ WZX = 50°
XW is not an altitude.
Step-by-step explanation:
16. See the attached figure.
XW is the angle bisector of ∠ YXZ, hence, ∠ WXY = ∠ WXZ
Now, given that ∠ YXZ = 8x + 34 and ∠ WXY = 10x - 13
Hence, ∠ YXZ = 2 ∠ WXY
⇒ 8x + 34 = 2(10x - 13)
⇒ 8x + 34 = 20x - 26
⇒ 12x = 60
⇒ x = 5.
Hence, ∠ XZY = ∠ WZX = 10x = 50° (Answer)
Now, ∠ WXZ = ∠ WXY = 10x - 13 = 37°
Hence, from Δ WXZ,
∠ WZX + ∠ WXZ + ∠ XWZ = 180°
⇒ 50° + 37° + ∠ XWZ = 180°
⇒ ∠ XWZ = 93° ≠ 90°
Hence, XW is not an altitude. (Answer)
