3 years ago

I don't understand this question.

Mathematics

1 answer:

OlgaM077 [116]3 years ago

3 0

X - y > 2 at (5, 4)
5 - 4 > 2
1 > 2

(5, 4) is not a solution to this inequality

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In a class of 20 students, the number of boys was the number of girls. How many girls were in the class?

Zielflug [23.3K]

Answer:

Step-by-step explanation:

Because if the number of girls is the same as the boys you just devide 20 by 2 and get 10

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3 years ago

Sadie sold 45 cupcakes, which were packed in 9 boxes. How many cupcakes were in each box? 4 5 8 9

Korvikt [17]

45 divided by 9 = 5
5 cupcakes per box

3 0

3 years ago

Read 2 more answers

Find the product please and thank you

crimeas [40]

You would multiply the power by the powers of both exponents
2 × 3 = 6 so a^6
3 × 4 = 12 so b^12
Answer is
a^6b^12

4 0

3 years ago

Veronica bought 20 bags of candy for a school dance. The first 5 bags cost $1.79 each. The rest of the bags cost $1.19 each. How

scZoUnD [109]

Answer:

$26.80

Step-by-step explanation:

multiply 1.79 by 5 and you get 8.95

multiply 1.19 by 15 now because there are 15 uncounted bags left and you get 17.85

add together and you get 26.8. she spent 26.8 dollars on candy

4 0

3 years ago

Find the 63rd term of the arithmetic sequence -1, 5, 11, ...−1,5,11,...

Ugo [173]

Answer:

$a_6_3=371$

Step-by-step explanation:

we know that

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant and this constant is called the common difference

we have

$-1,5,11,...$

Let

$a_1=-1\\a_2=5\\a_3=11$

$a_2-a_1=5-(-1)=5+1=6$

$a_3-a_2=11-5=6$

The common difference is $d=6$

We can write an Arithmetic Sequence as a rule

$a_n=a_1+d(n-1)$

where

a_n is the nth term

d is the common difference

a_1 is the first term

n is the number of terms

Find the 63rd term of the arithmetic sequence

we have

$n=63\\d=6\\a_1=-1$

substitute

$a_6_3=-1+6(63-1)$

$a_6_3=-1+6(62)$

$a_6_3=-1+372$

$a_6_3=371$

6 0

4 years ago