Combining like terms refers to adding all of the terms that have a exponent or a variable in an expression.
Example: 6y + 10y - 2
You would combine the like terms, which two numbers have a variable.
6y + 10y = 16y
After combing the like terms, the new expression should be:
16y - 2
Answer:
15°
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Step-by-step explanation:
Since P is on the median of ΔABC, it is equidistant from points B and C as well as from C and Q. Thus, points B, C, and Q all lie on a circle centered at P. (See the attached diagram.)
The base angles (B and C) of triangle ABC are (180° -30°)/2 = 75°. This means arc QC of the circle centered at P has measure 150°. The diameter of circle P that includes point Q is defined to intersect circle P at R.
Central angle RPC is the difference between arcs QR and QC, so is 180° -150° = 30°. Inscribed angle RQC has half that measure, so is 15°. Angle PQC has the same measure as angle RQC, so is 15°.
Angle PQC is 15°.
Answer:
The answer is B
Step-by-step explanation:
Answer:
At a speed of 2 km every 3 minutes, in 2 minutes the kangaroo would travel 1,333 km.
Step-by-step explanation:
If a kangaroo hops 2 kilometers in 3 minutes, to calculate how much distance this animal hops in 2 minutes, the following calculation should be performed:
2 km / 3 min = 0.666 km per minute (2/3 x 2)
0.666 km per minute x 2 minutes = 1.333 kilometers in 2 minutes (0.666 x 2)
Therefore, at a speed of 2 km every 3 minutes, in 2 minutes the kangaroo would hop 1,333 km.
Answer: The ramp would be 15.5 feet long.
Step-by-step explanation: Please refer to the attached diagram for details.
Angle C shows the angle to be formed by the ramp from the ground, which is 15 degrees. Also, from the ground, it’s going to be four feet tall, which is line AB. The top of the ramp is point A, which makes line AC the entire length of the ramp. Since we have a reference angle (angle C) and two sides, the opposite and the hypotenuse, we shall apply the trigonometric ratio.
SinC = opposite/hypotenuse
Sin 15 = 4/b
By cross multiplication we now have
b = 4/Sin15
b = 4/0.2588
b = 15.4599
Approximately b = 15.5
Therefore the length of the ramp would be 15.5 feet