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zepelin [54]
3 years ago
14

How do you simplify 2 15/10?

Mathematics
2 answers:
Brrunno [24]3 years ago
7 0
So you have to add another whole which is three then you take it away from the fifteen then you have 3 5/10 and simplify again and you get 4 1/2
 
sdas [7]3 years ago
6 0
First you take 15/10 and see that you can take 5 out of the top and bottom, so it would become 3/2. Now you have 2 3/2.   2 goes into 3 once with 1 remainder so 3/2= 1 1/2
So then you take the original 2 and add it to 1 1/2. The answer is now 3 1/2
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An investment company pays 8​% compounded semiannually. You want to have $12,000 in the future. (A) How much should you deposit
Leno4ka [110]
Before we start answering the question, let's define the compound interest formula:
A = P(1+ \frac{r}{n}) ^{nt}
Where:
<span>'A'</span>  is the amount of money in dollars
'P' is the principal amount of money in dollars
'r' is the interest rate (decimal)
'n' is the number of times interest is compounded per year
't' is the time in years

<span>(A) Find Principal Amount
</span><u /><span><u>Given:</u>
</span>A = 12,000
P = ?
r = 0.08
n = 2 (semiannually)
t = 5
Now we plug our values in and solve:
12,000 = P(1+ \frac{0.08}{2}) ^{(2)(5)}
12,000 = P(1.04) ^{10}
P = 8106.77
∴ You would have to deposit $8106.77 in order to have $12,000 in 5 years from now.

(B) Find Principal Amount
Same given values as above, with the exception of 't' which is now 10 instead of 5. 
12,000 = P(1+ \frac{0.08}{2}) ^{(2)(10)}
12,000 = P(1.04) ^{20}
P = 5476.64
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Hope this helps!
4 0
3 years ago
<img src="https://tex.z-dn.net/?f=4%20%5Cfrac%7B1%7D%7B9%7D%20%20%2B%201%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1" title="4 \
tino4ka555 [31]

Step-by-step explanation:

\tt{ 1. \:  \: 4 \frac{1}{9} + 1 \frac{1}{2}}

⇢ \tt{  \frac{37}{9}  +  \frac{3}{2} }

⇢ \tt{ \frac{37  \times 2 + 3 \times 9}{18} }

⇢ \tt{ \frac{74 + 27}{18} }

⇢ \tt{ \frac{101}{18}}

⇢ \boxed{ \tt{5 \frac{11}{18}} }

---------------------------------------------------------

\tt{ \: 2. \:  \: 4 \frac{1}{2} \div \frac{3}{5}}

⇢ \tt{ \frac{9}{2}  \times  \frac{5}{3}}

⇢ \tt{ \frac{9  \times 5}{2 \times 3}}

⇢ \tt{ \frac{45}{6}}

⇢ \boxed{ \tt{7 \frac{3}{6}} }

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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Three million twenty nine and two hundred fifty one




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Lisa [10]

Answer:

Option C is right.

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Length of AB = 8 and Length of A'B' = 4.

Hence A'B'C' is obtained by dilating ABC by a scale factor of 1/2.

Now since moved to III quadrant from I quadrant we find that there is a rotation of triangle ABC about the origin.  The degree of rotation is 180 degrees.

Hence A'B'C' is obtained by dilating ABC by a scale factor of 1/2 and then rotating it about the origin by 180 degrees

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