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2 years ago

What is the sample space for a spinner with four equal sections, numbered 1 to 4?

Mathematics

2 answers:

aev [14]2 years ago

3 0

1-1, 1-2, 1-3, 1-4 and u should Change it to middle school

pogonyaev2 years ago

3 0

Answer:

1/4

Step-by-step explanation:

there are 4 equal sides

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If you could show as much work as possible that would be amazing!!

Nikitich [7]

Answers:

Reduce:

Here we gave to simplify the expressions:

9) $x^{2}+7x+\frac{12}{x^{2}}+11x+28$

Grouping similar terms:

$(x^{2}+\frac{12}{x^{2}})+(18x+28)$

Applying common factor $x^{2}$ in the first parenthesis and common factor $2$ in the second parenthesis:

$x^{2}(1+\frac{12}{x^{4}})+2(9x+14)$ This is the answer

11) $y^{3}+\frac{27}{y^{2}}+2y-3$

Rearranging the terms:

$(y^{3}+2y)+(\frac{27}{y^{2}}-3)$

Applying common factor $y$ in the first parenthesis and common factor $3$ in the second parenthesis:

$y(y^{2}+2)+3(\frac{9}{y^{2}}-1)$ This is the answer

Multiply:

19) $(\frac{12a^{9}u^{7}}{15 c})(\frac{3c^{4}}{21a^{13 u^{8}}})$

Multiplying both fractions:

$\frac{36 a^{9}u^{7}c^{4}}{315 c a^{13}u^{8}}$

Dividing numerator and denominator by 3 and simplifying:

$\frac{12 c^{3}}{105 c a^{4}u}$ This is the answer

21) $(x-\frac{3}{x}-7)(x^{2}-9x+\frac{35}{x^{2}}-18)$

$(\frac{x^{2}-3-7x}{x})(\frac{x^{4}-9x^{3}+35-18x^{2}}{x^{2}})$

Operating with cross product:

$x^{2} (x^{2}-3-7x) x(x^{4}-9x^{3}+35-18x^{2})$

$x^{9} -9x^{8} -18x^{7}+35x^{5}-7x^{8} +63x^{7}+126x^{6}-245x^{4}-3x^{7}+27x^{6}+54x^{5}-105x^{3}$

Grouping similar terms and factoring:

$x^{9}-2(8x^{8}+21x^{7} )+153x^{6}+89x^{5}-5(49x^{4}+21x^{3})$ This is the answer

Divide:

29) $\frac{\frac{k^{6}}{x^{2}}}{\frac{2k^{4}}{3x^{6}}}$

$\frac{3k^{6}x^{6}}{2x^{2}k^{4}}$

Simplifying:

$\frac{3}{2} k^{2}x^{4}$ This is the answer

33) $\frac{\frac{x+5}{x+1}}{\frac{x^{2}+11x+30}{x^{2}+3x+2}}$

$\frac{(x+5)(x^{2}+3x+2)}{(x+1)(x^{2}+11x+30)}$

Factoring numerator and denominator:

$\frac{(x+5)(x+2)(x+1)}{(x+1)(x+6)(x+5)}$

Simplifying:

$\frac{x+2}{x+6}$ This is the answer

37) $\frac{\frac{x-10}{x+13}}{\frac{x^{3}-1000}{x^{2}+15x+21}}$

$\frac{(x-10)(x^{2}+15x+21)}{(x+13)(x^{3}-1000)}$

Applying the distributive property in numerator and denominator:

$\frac{x^{3}+15x^{2}+21x-10x^{2}-150x-210}{(x+13)(x^{4}-1000x+13x^{3}-13000)}$

Grouping similar terms and factoring by common factor:

$-\frac{5x(x^{2}-129)(x^{2}-42)}{1000x^{3} (x+13)(x-13)}$

Dividing by $5$ in numerator and denominator and simplifying:

$-\frac{(x^{2}-129)(x^{2}-42)}{200x^{2}(x+13)(x-13)}$ This is the answer

3 0

3 years ago

Help a brother out!!! Math prom worth 20!! And explain please

Reil [10]

A.

ratio 1 to 1

alright
find the distance between the x values and the y values and seperate each into that ratio
1:1
A to B is (6,12) to (15,-4)
disatnce from 6 to 15 is 9, ratio would be 4.5:4.5=1:1
distance from 12 to -4 is 16, ratio would be 8:8=1:1
so the point would be (4.5,8)

b.
5:2
5+2=7
alright
A to C
(6,12) to (20,12)
distance from 6 to 20 is 14, 14/7=2, 2 times 5=10
distance from 12 to 12=0, so same coordinate
the point is (10,12)

c.
2+3=5

C to B
C is (20,12) and B is (15,-4)
distance from 20 to 15 is 5, so 2 is the x value
distance from 12 to -4 is 16, 16/5 times 2=32/5
the point is (2,32/5)

5 0

3 years ago

Use calculus to find the area of the triangle with the vertices (0, 5), (2, -2), and (5, 1).

guajiro [1.7K]

The area of the triangle with the vertices (0, 5), (2, -2), and (5, 1) by using the calculus is 21 square unit.

We need to find the equation among all possible pairs and then integrate the equations from one co-ordinate to another co-ordinate

Equation of line passing through (0,5) and (2,-2) is

y-5 = [(-2-5)/(2-0)](x-0)

=>y-5 = (-7) /2x

=>y= (-7/2x)+5 -------(eq1)

Equation of line passing through (0,5) and (5,1) is

y-5 = [(1-5) / (5-0)](x-0)

=>y-5 = (-4/5)x

=>y = (-4/5)x+5-------(eq2)

Equation of line passing from (2,-2) and (5,1) is

y-(-2) = [[1 - (-2)] / (5-2)] / (x-2)

=>y+2=(3/3)(x-2)

=>y=x-4--------(eq3)

Now, we use definite integration to find the area between the different equation of line.

So, area enclosed between the equations is given by the

area = $\int\limits^5_2$ [(-4/5)x+5 - (-7/2)x + 5)dx + $\int\limits^5_1$ [(-4/5)x+5 -(x-4)]dx

=>area= $\int\limits^5_2$ (7/2-4/5)x dx + $\int\limits^5_1$ ((-9/5)x+9)dx

Using properties of integration, $\int\limits x\, dx=x^{2}/2$

=>area= $\int\limits^5_2$ (27/10)x dx + $\int\limits^5_1$ (-9/5)x+9)dx

=>area=([27/10)×[5² - 2²])/2 + [ (-9/5)×(5²-1²) ]/2 +9×(5-1)

=>area=(27/20)×(25-4) + (-9/5)×24+9×4

=>area = (27×21)/20 + (-216)/5+ 36

=>area=(567/20) - (216/5) + 36

=>area= [(567-261×4)+(36×20)]/20

=>area=[(567-864)+720]/20

=>area=423/20

=>area=21 square unit.

Hence, area of triangle is 21 square unit.

To know more about area of triangle, visit here:

brainly.com/question/19305981

#SPJ4

4 0

1 year ago

What is the colon form? :)

Ann [662]

Answer and Step-by-step explanation:

I think this is correct? The directions aren't very clear/descriptive, so sorry if this is wrong.

1. wins:games

2. wins:losses

3. losses:wins

4. games played:wins

5. losses:games played

1. 8:12, or 2:3

2. 3:7

3. 5:3

4. 12:15, or 4:5

5. 20:25, or 4:5

#teamtrees #PAW (Plant And Water)

4 0

2 years ago

Consider the inequality -5(x+7) <-10. write an inequalityrepresenting the soulution for x.

Gwar [14]

Answer:

x > -5

Step-by-step explanation:

You multiply both sides by -1

Simplify

Divide both sides by 5

Simplify

Subtract 7 from both sides

Simplify

Please give me BRAINLIEST and THANKS lol <(￣︶￣)>

6 0

2 years ago