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sweet-ann [11.9K]
3 years ago
13

Please help Write an inequatily to describe the relationship between -1 2/3 and -1/4​

Mathematics
1 answer:
Mamont248 [21]3 years ago
6 0

Answer:-1 2/3 > -1/4

Step-by-step explanation:

-1 2/3 , -1/4

-5/3 , -1/4

-20-3/12

Therefore;-1 2/3 >-1/4

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After using some of the honey they collected for baking, they found that they only had 34 gallon of honey left. How much honey d
bogdanovich [222]

Answer:

34 gallons of honey left

Step-by-step explanation:

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3 years ago
Please help if it's right I'll give brainliest
kari74 [83]

Answer:

Since XBC is 55 degrees and triangle BXC is isosolese, angle BCX is also 55 degrees. 180 - 110 = 70

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7 0
2 years ago
Hey guys please solve this basic equation for me <br> 5 + 2x &lt; 9
nikitadnepr [17]

Answer:

x < 2

Step-by-step explanation:

Given

5 + 2x < 9 ( subtract 5 from both sides )

2x < 4 ( divide both sides by 2 )

x < 2

6 0
3 years ago
Which expression is equal to (f · g)(x)?
CaHeK987 [17]

Answer:

A

Step-by-step explanation:

Note that

x² + 12x + 36 is a perfect square → (x + 6)², hence

\sqrt{x^2+12x+36} = \sqrt{(x+6)^2} = (x + 6)

Hence

f(x) × g(x)

= (x + 6)(x³ - 11)

= x^{4} - 11x + 6x³ - 66

= x^{4} + 6x³ - 11x - 66 → A

4 0
3 years ago
If
baherus [9]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: cos 330 = \frac{\sqrt3}{2}

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}

Proof LHS → RHS:

LHS                          cos 165

Double-Angle:        cos (2 · 165) = 2 cos² 165 - 1

                             ⇒ cos 330 = 2 cos² 165 - 1

                             ⇒ 2 cos² 165  = cos 330 + 1

Given:                        2 \cos^2 165  = \dfrac{\sqrt3}{2} + 1

                              \rightarrow 2 \cos^2 165  = \dfrac{\sqrt3}{2} + \dfrac{2}{2}

Divide by 2:               \cos^2 165  = \dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \dfrac{2\sqrt3+4}{8}

Square root:             \sqrt{\cos^2 165}  = \sqrt{\dfrac{4+2\sqrt3}{8}}

Scratchwork:            \cos^2 165  = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2

                             \rightarrow \cos 165  = \pm \dfrac{\sqrt3+1}{2\sqrt2}

             Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

                             \rightarrow \cos 165  = - \dfrac{\sqrt3+1}{2\sqrt2}

LHS = RHS \checkmark

4 0
4 years ago
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