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3 years ago

Y + 2 =3 (x-6) find the slope and a point on the line

Mathematics

1 answer:

Alex777 [14]3 years ago

5 0

Answer:

slope = 3, point = (6, -2)

Step-by-step explanation:

This is in point-slope form which looks like this : y-y1 = m(x-x1).

m is the slope, an x1 and y1 are the x and y coordinates of the point. Remember to flip the sign of the numbers for the points i.e. the y+2 in the equation becomes -2 for the point.

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Suppose f (x) = x^2. Find the graph of f(x+2)

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$\bf ~~~~~~~~~~~~\textit{function transformations}
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f(x)={{ A}}({{ B}}x+{{ C}})+{{ D}}
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\\\\
f(x)={{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
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f(x)={{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
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$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
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\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
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$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
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with that template in mind,

$\bf f(x)=x^2\qquad \quad f(x+2)=(x+2)^2\implies f(x+2)=\stackrel{A}{1}(\stackrel{B}{1}x\stackrel{C}{+2})^2\stackrel{D}{+0}$

C = 2 B = 1 C/B = 2/1 or +2, horizontal left shift of 2 units

f(x) shifted left by 2 units is f(x+2).

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Question 6<br> Find the slope of the line passing through the points (11,-5) and (11,6)

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Y + 2 =3 (x-6) find the slope and a point on the line​

Y + 2 =3 (x-6) find the slope and a point on the line