3 years ago

Is there a solution to 2x^2+7x-4=0?

2 answers:

8 0

Ax^2+bx+c=0
always answer is:
-b+(b^2-4ac)/2a
and
-b-(b^2-4ac)/2a

3 0

Answer:

x= -8 x= 1

Step-by-step explanation:

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earnstyle [38]

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Step-by-step explanation:

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4 years ago

Alexxx [7]

The total amount of angles in quadrilateral is 360.so:

z=360-(122+79+90)
z=360-291
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3 years ago

jenyasd209 [6]

Regular= 3/5 equivalent= 6/10 just multiply the top and bottom by the same number.

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3 years ago

-BARSIC- [3]

Step-by-step explanation:

it will be answer B

2x^3+6x^2-4x-12

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dangina [55]

5x+9 = 10x-9
Take 5x from both sides
9 = 5x-9
Add 9 to both sides
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Divide by 5
3.6=x

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3 years ago