Question

Find the equation in standard form of the line passing through the points (2,-3) and (4,2)

Answer 1

The line passes through (2,-3) and (4,2).

Calculate the slope of the line.
m = (2+3)/(4-2) = 5/2

The equation of the line is therefore
$\frac{y-2}{x-4} = \frac{5}{2}$

Cross multiply.
2(y-2) = 5(x-4)
2y - 4 = 5x - 20
2y = 5x - 16
Rewrite as
5x - 2y = 16

Answer: C. 5x - 2y = 16