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RSB [31]
3 years ago
9

Jack said, "five times my age in 2 years is 100." How old is jack now?

Mathematics
2 answers:
denpristay [2]3 years ago
6 0
10 ???? im Guessing.. Hope Its Right (: pretty sure it is ..
Naya [18.7K]3 years ago
4 0
It's 18 because if you had 2 to 18 you get 20. 20 multiplied by 5 is 100. Hope this helped.
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I need help w this soon
Shtirlitz [24]

Answer:

18

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
A Pac-Man poster is the shape of three-fourths of a circle with a diameter of 18 inches and two sides that are 9 inches each. Wh
slava [35]

Answer:

60.39 inches

Step-by-step explanation:

Given that:

A Pac-Man poster which is having three fourth of a circle and there are two sides.

Diameter of circle = 18 inches

Sides of Pac-Man poster = 9 inches

To find:

Perimeter of the Pac-Man poster.

Solution:

Perimeter of a figure is nothing but equal to the periphery i.e. the outer area of the circle/figure.

Perimeter of a circle is given by the formula:

Perimeter = 2\pi r

r is the radius of the circle.

Radius is half of perimeter.

r=\dfrac{18}{2} = 9\ inches

Perimeter of the Pac-Man poster = Perimeter of \frac{3}{4} circle + 2 sides

Perimeter of the Pac-Man poster = \frac{3}{4}\times 2\times \pi \times 9  + 9+9 = 42.39+28 = <em>60.39 inches</em>

7 0
2 years ago
If f(x) = 3x - 1 and g(x) = x + 2, find (f - g)(x).
Marina86 [1]

Answer:

\boxed{\sf (f - g)(x) = 2x - 3}

Given:

f(x) = 3x - 1

g(x) = x + 2

To Find:

(f - g)(x)

Step-by-step explanation:

\sf (f -g)(x) = f(x) - g(x) \\ \\   \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \: =(3x - 1) - (x + 2) \\  \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \: =3x - 1 - x - 2 \\  \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \: =3x - x - 1 - 2 \\  \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \: =(3x - x) - (1 + 2) \\  \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \: =2x - (1 + 2) \\  \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \: =2x - 3

6 0
3 years ago
Find the polynomial f(x) of degree 3 with real coefficients that has a y-intercept of 60 and zeros 3 and 1+3i.
Sauron [17]

\bf \begin{cases} x=3\implies &x-3=0\\ x=1+3i\implies &x-1-3i=0\\ x=1-3i\implies &x-1+3i=0 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ (x-3)(x-1-3i)(x-1+3i)=0 \\\\\\ (x-3)\underset{\textit{difference of squares}}{([x-1]-3i)([x-1]+3i)}=0\implies (x-3)([x-1]^2-[3i]^2)=0 \\\\\\ (x-3)([x^2-2x+1]-[3^2i^2])=0\implies (x-3)([x^2-2x+1]-[9(-1)])=0

[ correction added, Thanks to @stef68 ]

\bf (x-3)([x^2-2x+1]+9)=0\implies (x-3)(x^2-2x+10)=0 \\\\\\ x^3-2x^2+10x-3x^2+6x-30=0\implies x^3-5x^2+16x-30=f(x) \\\\\\ \stackrel{\textit{applying a translation with a -2f(x)}}{-2(x^3-5x^2+16x-30)=f(x)}\implies -2x^3+10x^2-32x+60=f(x)

5 0
3 years ago
Which statements are true about the interquartile range? Select all that apply. Subtract the lowest and highest values to find t
katen-ka-za [31]

Answer:

The correct options are:

Interquartile ranges are not significantly impacted by outliers.

Lower and upper quartiles are needed to find the interquartile range.

The data values should be listed in order before trying to find the interquartile range.


The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range.

The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median

6 0
3 years ago
Read 2 more answers
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