The circumference is πd, and the diameter is 10, so the circumference is 10π. All sides of a square are equal, so the length of each side is 10π/4, which is 2.5π.

The length of each side of the square is 2.5π

7 0

3 years ago

Please help me I would really appreciate it.

Karo-lina-s [1.5K]

Given:

$\overline{AB}\cong \overline {CD},\overline{BC}\cong \overline {DA}$

To prove:

$\Delta CDA\cong \Delta ABC$

Proof:

In $\Delta CDA\text{ and } \Delta ABC$ ,

$\overline{AB}\cong \overline {CD}$ because Given

$\overline{BC}\cong \overline {DA}$ because Given

$\overline{AC}\cong \overline {AC}$ because Reflexive property.

Corresponding sides of both triangles are congruent. So,

$\Delta CDA\cong \Delta ABC$ because SSS

Therefore, the required missing values are: Given, $\overline{BC}\cong \overline {DA}$ , Reflexive property , $\Delta CDA\cong \Delta ABC$ , SSS respectively.

5 0

2 years ago

Simplify: (7x^2 − 8x − 4) + (−2x^2 + 3x + 5) + (5x^2 − 10x − 8)

kramer

Step 1. Simplify
7x^2 - 8x - 4 - 2x^2 + 3x + 5 + 5x^2 - 10x - 8
Step 2. Collect like terms
(7x^2 - 2x^2 + 5x^2) + (-8x + 3x - 10x) + (-4 + 5 - 8)
Step 3. Simplify

10x^2 - 15x - 7

5 0

2 years ago

1. Knowing that the area of a rectangle and a parallelogram is (base * height), use the given side length and

astraxan [27]

Answer:

51.84sq

Step-by-step explanation:

4 0

3 years ago