Answer:
No, it is not possible.
Step-by-step explanation:
A system of linear equations with infinitely many solutions must meet at every single point. That means they have both the same y-intercept and the same slope. If either one of those are different, there cannot be infinitely many solutions.
I think it is 32, bc the value of x is 20 so your problem would look like this; 2 ( (20) - 4 )
Answer:
1/cos^2(180-theta) - 1
Step-by-step explanation:
According to trigonometry identity
tan^2 theta + 1 = sec^2 theta
tan^2 theta = sec^2 theta - 1
hence tan^2(180-tetha) = sec^2 (180 -theta) - 1
tan^2(180-tetha) = 1/cos^2(180-theta) - 1
Hence the value of tan^2(180-tetha) is 1/cos^2(180-theta) - 1
Answer:
y=−2
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
6y+2(3y−5)=−34
6y+(2)(3y)+(2)(−5)=−34(Distribute)
6y+6y+−10=−34
(6y+6y)+(−10)=−34(Combine Like Terms)
12y+−10=−34
12y−10=−34
Step 2: Add 10 to both sides.
12y−10+10=−34+10
12y=−24
Step 3: Divide both sides by 12.
=
y=−2
This is the concept of polynomials, to get the relationship between the (x-3) and (x^3+4x^2+2) we shall proceed as follows;
we first test if (x-3) is a polynomial;
x-3=0
thus;
x=3
substituting the value of x in the polynomial we get:
(3)^3+4(3)^2+2
=65
since the result is not equal to 0, we conclude that there is no relationship between (x-3) and the polynomial. The answer is B. (X-3) is not a factor