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geniusboy [140]
3 years ago
13

What is the product of 3*the square root of 6 and 5*the square root of 12 in simplest radical form

Mathematics
1 answer:
ira [324]3 years ago
8 0

√
6
⋅
√
15
=
3
√
10

Explanation: By radical laws,
√
a
⋅
√
b
=
√
a
b
.
Using this law:
√6⋅√15
=√90

√90 has 9, a perfect square, as one of its factors, so it can be simplified.
√90
=√9⋅10
=√9⋅√10

=3√10
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The angle of elevation from Madison to the top of the Statue of Liberty is 79 degrees. If Madison is standing 58.2 feet from its
lana66690 [7]
To solve this problem you must apply the proccedure shown below:

 1. You have the following information given in the problem:

 - <span>The angle of elevation from Madison to the top of the Statue of Liberty is 79 degrees.
 - Madison is standing 58.2 feet from its base.

 -Madison is 5 feet tall.

 2. Therefore, you have:

 Sin</span>α=opposite/hypotenuse
<span>
 Sin(79°)=x/58.2
 x=(58.2)(Sin(79°))
 x=57.13 ft

 3. Now, you can calculate the height of the Statue of Liberty, as below:

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What is the wavelength of a 320 Hz sound traveling 330 m/s?
maw [93]

Answer:1.03125 meter

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8 0
4 years ago
1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n
Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 70% of fatalities involve an intoxicated driver, hence p = 0.7.
  • A sample of 15 fatalities is taken, hence n = 15.

The probability is:

P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)

Hence

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061

P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186

P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700

P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916

P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305

P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047

Then:

P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

5 0
3 years ago
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