We have been given two matrices a and b. A has 6 rows and 7 columns, while b has 7 rows and 8 columns.
Since we know that order matters in matrix multiplication. In order for matrix multiplication to be defined number of columns in the first matrix should be equal to the number of rows of in the second matrix.
We can see that number of columns in matrix a and number of rows in matrix b is 7.
Therefore, size of ab will be equal to number of rows of matrix a and number of columns of matrix b that is 6 by 8.
Now we will see whether ba is defined or not. We can see columns in matrix b are 8 and rows in matrix a are 6, which is not equal. So we can say that ba is not defined.
Therefore, size of ba is not defined (dne).
Answer:
assuming only positive integers, the answer is 1
Step-by-step explanation:
the smallest number that you can get by adding is:
- start with 0
- then add 1 = 1
- add another 1 = 2
- add another 1 = 3
- add another 1 = 4
- add another 1 = 5
but you can also multiply, and anything multiplied by 0 is 0:
- start with 0
- multiply by 2 = 0
- multiply by 2 = 0
- multiply by 2 = 0
- multiply by 2 = 0
- multiply by 2 = 0
The question does not say that we need to do any specific calculation, it only gives us 2 options and we can choose them as many times as we want.
Answer:
Right Isosceles
Step-by-step explanation:
First, let's see if this triangle is Acute, Obtuse or Right.
We see that PB and QB are perpendicular lines, meaning that they form a right angle. Therefore, triangle PQB is a right triangle.
Next, let's see if this triangle is equilateral, isosceles or scalene. PB and QB are congruent side lengths but PQ is not congruent to either PB or QB. Therefore, because two of the side lengths are congruent to each other and one is not, then triangle PQB is a isosceles triangle.
In conclusion, triangle PQB can be categorized as a right isosceles triangle.
Hope this helps!
Solution:
Using Substitution Method:
-4x+7y=-5 (Equation 1)
x-3y=-5 (Equation 2)
get the value of x from Equation 2
x=3y-5 (Equation 3)
Put the value of x from Equation 3 in Equation 1
-4(3y-5)+7y=-5
-4(3y)+20+7y=-5
-12y+7y=-5-20
-5y=-25
Negative sign on both sides cancels each other
y=25/5
y=5
Putting value of y in equation 3
x=3(5)-5
x=15-5
x=10
Therefore, [x,y]=[10,5]
Using Elimination Method
-4x+7y=-5 (Equation 1)
x-3y=-5 (Equation 2)
Multiply equation 2 with -4 in order to eliminate the x term
-4(x-3y)=-5*4
-4x+12y=20 (Equation 3)
Adding Equation 1 and 3
-4x+7y=-5
-4x+12y=20
+ - = - (Change Of Sign with x and y terms)
-----------------
0x-5y = -25
-5y=-25
y=5
Substituting y’s value is Equation 1
-4x+7(5)=-5
-4x+35=-5
-4x=-40
Cancellation of negative sign on both sides
x=40/4
x=10
[x,y]=[10,5]
Answer:
88
Step-by-step explanation:
8x8=64
1/2(8x6)=24
64+24=88
