Answer:
17.5% of 360 = 63
Step-by-step explanation:
We are given a process of finding 17.5% of 120. Following the same process we have to determine the 17.5% of 360.
17.5% can be break down as 10% + 5% + 2.5%
Thus,
STEP 1 : Find 10% of 360 , we get,

STEP 2 : find 5% of 360, we get,

STEP 3: find 2.5% of 360 , we get,

STEP 4: 17.5% of 360 = 10% of 360 + 5% of 360 + 2.5% of 360
⇒ 17.5% of 360 = 36 + 18 + 9
⇒ 17.5% of 360 = 63
Answer:
theta = 4.5642792103077898247
Step-by-step explanation:
0 <= theta < 2Pi sin(theta) = 1/2
so
2Pi sin(theta) = 1/2
Pi sin(theta) = 1/4
sin(theta) = 1/(4Pi)
sin(theta) = .0795774715459
theta = arcsin(.0795774715459) = 4.5642792103077898247
Answer:
-16
Step-by-step explanation:
So you want to change the - into a + and the negative sign before the 13 also into a plus. So it is -29 + 13 and that would be -16 ^.^ Hope this helped!!
Answer:
c)30%
Step-by-step explanation:
Step one:
given data
The shopkeeper said each pair of earrings cost Rs. 12
if he offered 12 pairs for Rs. 100.
let us find the cost per pair
= 100/12
=Rs. 8.3 per pair
Required
The percent discount
Step two:
%percent discount= 12-8.3/12*100
%percent discount= 3.66/12*100
%percent discount= 0.305*100
%percent discount= 30.5%
Answer:
You could not use a table with a top that is 2 1/2 feet long and 1 1/2 feet wide
Step-by-step explanation:
<u><em>The complete question is</em></u>
Elena needs to find a table that will fit three cube-shaped cases, each containing a frog.If the volume of each case is 1,000 cubic inches, could she use a table with a top that measures 2 1/2 feet long and 1 1/2 feet wide?Explain
step 1
Find the length side of the cube-shaped case
we know that
The volume of the cube is equal to

where
b is the length side of the cube
we have

substitute

solve for b

step 2
Convert feet to inches

we have


step 3
Compare the dimensions of the table with the dimensions of the cube-shaped case
30 > 10
The length of the table is greater than the length side of the cube
18> 10
The width of the table is greater than the length side of the cube
therefore
You could not use a table with a top that is 2 1/2 feet long and 1 1/2 feet wide