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viva [34]
4 years ago
14

I want to ask for solutions of question 19 and 20

Mathematics
1 answer:
laila [671]4 years ago
4 0
Need a better picture please so I can help
You might be interested in
In a bag are 3 red, 9 blue, 2 yellow and 3 green marbles. If you draw out a marble at random, what the probability that you will
dmitriy555 [2]

Answer:

9/17

Step-by-step explanation:

there are 17 marbles in total 9 of them are blue therefore, 9/17 is the correct answer

6 0
3 years ago
if alpha and beta are the roots of the equation 2 x square - 7 x - 3 is equal to 0 find alpha + beta​
Lorico [155]

Answer:

Values for alpha and beta are 0.5 and 3.

Step-by-step explanation:

2x² - 7x - 3 = 0

2x² - 7x - 3 = (2x - 1 )(x - 3)

∴ (2x - 1 )(x - 3) = 0

The only way to get zero by multiplying two values together, is if one of those values is qual to zero. Therefore, either (2x - 1 )=0, or (x - 3)=0.

If (2x - 1 )=0

∴2x=1

∴x=0.5

If (x - 3)=0

∴x=3

We have two values for x. These values represent alpha and beta.

<em>(BTW - I'm not sure from the phrasing of your question whether or not you just want to find the values or whether you want to find the sum of the values (I don't know if you used '+' to mean 'and' or 'plus'), but if you do want to find the sum, it's of course just 0.5+3= 3.5.)</em>

8 0
3 years ago
What is the value of x in the diagram below?
vesna_86 [32]
I think it’s 11. Sorry if it’s wrong
7 0
3 years ago
If P=2L+2W, solve for W.
vodka [1.7K]

Answer:

W = (P-2L)/2

Step-by-step explanation:

Isolate W

P = 2L + 2W

subtract 2L from each side

P - 2L = 2W

divide each side by 2

(P-2L)/2 = W

3 0
3 years ago
Does there exist a pair of consecutive even integers whose reciprocals sum to 3/4? Explain how you know.
slamgirl [31]

Answer:

2, 4

Step-by-step explanation:

Let there are two unknown consecutive pairs of even integers 2n and 2n+2.

If the sum of the reciprocals of those two integers  is 3/4, then we can write,

1/2n +1/(2n+2) =3/4 ...... (1)

Solving this above equation we can check whether the integers exist or not.

Now, from equation (1) we get,

1/n +1/(n+1) =3/2

⇒2(2n+1)=3n(n+1)

⇒4n +2 =3n²+3n

⇒3n²-n-2 =0

⇒ (n-1)(3n+2) =0

⇒ (n-1) =0 {Since if (3n+2) =0 then, n will be a negative fraction, which is not possible}

⇒ n=1

∴ 2n =2 and 2n+2 =4

Hence, the two integers are 2, 4. (Answer)

4 0
3 years ago
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