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zmey [24]
3 years ago
10

A rectangular book measures 18 x 9. What is the length of its diagonal? Round your answer to the nearest tenth

Mathematics
1 answer:
avanturin [10]3 years ago
6 0

Answer:

20.1246118 or 20.12

Step-by-step explanation:

First draw the box with the diagonal, as you can see it is split into 2 equal right triangles. Now use the pythagorean theorem (a^2+b^2=c^2) to find the length of the diagonal

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For which equation would x = 8 not be a solution?
Olegator [25]

Answer:

b. 4x = 48

Step-by-step explanation:

If you look closely an multiply 4 x 8, it equals 32, not 48

The other equations:

8 x 8 does equal 64

10 x 8 does equal 80

9 x 8 does equal 72

It's pretty simple once you try each problem first

Hope this helps!

5 0
3 years ago
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Estimate how much 10.25 and 30.5
Elza [17]
I don't really get what you are asking for. Can you clarify it?
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I need help writing the expressions
True [87]

Answer:

Company a= 15x+10y+25z+75

Company b=20x+10y+30z+60

Step-by-step explanation:

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2 years ago
What is the cost of one cranberry and one banana nut muffin?
Bezzdna [24]
So for the cranberry muffin, for every 12 (a dozen) it's $3
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What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c
zysi [14]

Answer:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

Step-by-step explanation:

Given

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Required

Simplify

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Cancel out 18

\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}

Divide 4 and 2

\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}

Divide 27 and 12 by 3

\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}

Apply law of indices

\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}

\frac{9a^5 * b^3 * 2c }{4}

Divide 2 and 4

\frac{9a^5 * b^3 * c}{2}

\frac{9a^5b^3c}{2}

Rewrite as:

\frac{9}{2}a^5b^3c

Hence:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

4 0
2 years ago
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